We have q
consecutive integers in a set and q is odd.
If 120 is the middle number, then
there will be (q-1)/2 numbers
both before
and after 120.
Therefore, the largest number will
be (q-1)/2+120.
One of the numbers is 40 and the other one is 63
confirmation:
63×(2/3)-2=40
and 40+63=103
Answer:
56 because you have to multiply 28 times 2
Answer:
Besides the givens:
12.
AC = EC, BC = DC; Definition of Midpoint
<ACB = <ECD; Vertical Angles Theorem
Triangle ABC = Triangle EDC; SAS Congruence Postulate
13.
AD = CD; Definition of Median
BD = BD; Reflexive Property
Triangle ABD = Triangle CBD; SSS Postulate
Step-by-step explanation:
None necessary.
100%, since 5/5 is equal to 1, which is 100%.