What’s the slope intercept form of the equation through the points (-2, -1) and (-4, -3)?

1 answer:

3 0

$(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{-3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{-4}-\underset{x_1}{(-2)}}}\implies \cfrac{-3+1}{-4+2}\implies \cfrac{-2}{-2}\implies 1$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{1}(x-\stackrel{x_1}{(-2)})\implies y+1=1(x+2) \\\\\\ y+1=x+2\implies y=x+1$

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