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AnnZ [28]
3 years ago
9

Hi sorry to disturb you all but can you please help me divide this problem, thank you soo much

Mathematics
2 answers:
4vir4ik [10]3 years ago
8 0

Answer:

Exact from: 11/4

Decimal from: 2.75

Mixed number form: 2 3/4

Hope this helps! good luck :)

AURORKA [14]3 years ago
6 0

Answer: The Answer is 2.75

Step-by-step explanation: You first want to see how many times 56 goes into 1, which is 0, so you leave the space blank.

Then you want to drop down the 5 to get 15, and then you want to see how many times 56 can go into 15, which is 0, so you leave that space blank.

Next you want to bring down the 4 to get 154, and then see how many times 56 goes into it, which is 2 times, so you add a two in the ones place. Next you want to add two zeros after the decimal place behind the 4. You keep on bring down the numbers and seeing how many times 56 can go into them until you get your answer of 2.75.

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The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f
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Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

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substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)\\C=6\pi\ cm

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

Find the perimeter

P=(6\pi+12\sqrt{2})\ cm

simplify

Factor 6

P=6(\pi+2\sqrt{2})\ cm

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