Molar mass of H₂ = 1.008 × 2 g/mol = 2.016 g/mol <span>
Molar mass of I₂ =
126.9 × 2 g/mol = 253.8 g/mol </span><span>
Molar mass of HI = (1.008 + 126.9) g/mol = 127.9 g/mol
H₂(g) + I₂(g) → 2HI </span><span>
Mole ratio H₂ : I₂ : HI = 1 : 1 : 2 </span><span>
Then the initial number of moles of H₂ = (3.35 g) / (2.016 g/mol) = 1.662 mol </span><span>
Initial number of moles of I₂ = (50.75 g) / (253.8 g/mol) = 0.2000 mol <
1.662 mol </span><span>
Hence, I₂ is the
limiting reactant (limiting reagent). </span><span>
Number of moles of I₂ reacted = 0.2000 mol </span><span>
Number of moles of HI reacted = (0.2000 mol) × 2 = 0.4000 mol
<span>Mass of HI reacted = (127.9 g/mol) × (0.4000 mol) = 51.16 g</span></span>
C) alternating current .
<span>
B)direct current </span>
We can do this with the conservation of momentum. The fact it is elastic means no KE is lost so we don't have to worry about the loss due to sound energy etc.
Firstly, let's calculate the momentum of both objects using p=mv:
Object 1:
p = 0.75 x 8.5 = 6.375 kgm/s
Object 2 (we will make this one negative as it is travelling in the opposite direction):
p = 0.65 x -(7.2) = -4.68 kgm/s
Based on this we know that the momentum is going to be in the direction of object one, and will be 6.375-4.68=1.695 kgm/s
Substituting this into p=mv again:
1.695 = (0.75+0.65) x v
Note I assume here the objects stick together, it doesn't specify - it should!
1.695 = 1.4v
v=1.695/1.4 = 1.2 m/s to the right (to 2sf)
Answer:A:The track pushes back on Clinton's shoe with the same force.
Explanation:According to Newton's third law of motion, for every action force there is an equal and opposite reaction force. In this case, the action force is Clinton's shoe pushing on the track. As this happens, there is an equal and opposite reaction force in which the track pushes back on Clinton's shoe with the same force.
