Answer : The O-O bond in 
will be longer than the O-O bond in 
.
Explanation :
In the , the two oxygen atoms are bonded by the single bond and in , the two oxygen atoms are bonded by the double bond.
As we know, the bond strength of double bond is greater than the single bond.
And the relation between the bond strength and bond length is,
That means the higher the strength, the shorter will be the bond length.
Hence, the bond length of single bond will be longer than the double bond.
The structure of given molecule is shown below.
To convert from L to ml, we move three spaces to the right and the decimal place moves three places.
Our task here is to convert 600 L to mL. we have to remember that to convert from L to ml, we have to multiply the value in L by 1000
In other words, the value 1000 is known as the conversion factor.
When we do this, we move the decimal place three places to the right to have 600000.00mL
For more about conversion factors, see:
brainly.com/question/8512113
Answer:
The percent yield of NaCl is 78.7 %
Explanation:
CuCl₂ + 2NaNO₃ → Cu(NO₃)₂ + 2NaCl
If the NaNO₃ is determined to be in excess, the limiting reagent is the chloride. We convert the mass to moles:
31 g . 1mol / 134.45g = 0.230 moles
Ratio is 1:2, so we can make a rule of three to determine the theoretical yield
1 mol of copper (II) chloride reacts to produce 2 moles of sodium chloride
Then, 0.230 moles of CuCl₂ will react to produce (0.230 .2) /1 ) = 0.461 moles of NaCl → we convert the moles to mass → 0.461 mol . 58.45 g / 1mol = 26.9 g
To find percent yield we do → (Yield produced / Theoretical yield) . 100
(21.2 g / 26.9 g) . 100 = 78.7 %
Answer:
The partial pressure of the gas produced by the reaction is 0.9187 atm
Explanation:
Given;
vapor pressure of water, 
= 0.0313 atm
measured atmospheric pressure, 
= 0.950 atm
partial pressure of the gas produced by the reaction = ?
According to Dalton's law of partial pressure; total pressure is equal to sum of partial pressure of water vapor and gas produced.
= 
= 0.95 - 0.0313
= 0.9187 atm
Therefore, the partial pressure of the gas produced by the reaction is 0.9187 atm
Answer:
5.386m/s
Explanation:
kinetic energy is K = 1/2 *m*v^2
Velocity:
v = (2K / m) ^(1/2)
v = (2 * 1085 (kg*m^2 /s^2) /74.8kg) ^ (1/2)
v = 5,386m/s
(Remember:
N = kg * m^2 / s^2
()^1/2 is equal to square root)
