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Paladinen [302]
3 years ago
13

Solve: 2 3/4 −(−1 1/2 )+(− 5/6 )−(− 3/8)−(+4 2/3 ) PLS HELP!

Mathematics
2 answers:
neonofarm [45]3 years ago
3 0

Answer: -7/8

Step-by-step explanation:

you need to find a common denominator for all of them

in this case it would be 24

2 18/24 -(- 1 12/24) + (-20/24) -(-9/24) - (+ 4 16/24)

2 18/24 + 1 12/24 - 20/24 + 9/24 - 4 16/24

4 6/24 - 20/24 + 9/24 - 4 16/24

3 10/24 + 9/24 - 4 16/24

3 19/24 - 4 16/24

- 21/24

-7/8

makvit [3.9K]3 years ago
3 0

Answer:

-7/8

Step-by-step explanation:

2 18/24 -(- 1 12/24) + (-20/24) -(-9/24) - (+ 4 16/24)

2 18/24 + 1 12/24 - 20/24 + 9/24 - 4 16/24

4 6/24 - 20/24 + 9/24 - 4 16/24

3 10/24 + 9/24 - 4 16/24

3 19/24 - 4 16/24

- 21/24

-7/8

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Answer:

An old bone contains 80% of its original carbon-14 in 1844.6479 years

Step-by-step explanation:

We know that

half life time of C-14 is 5730 years

so, h=5730

now, we can use formula

P(t)=P_0(\frac{1}{2})^{\frac{t}{h} }

we can plug back h

and we get

P(t)=P_0(\frac{1}{2})^{\frac{t}{5730} }

An old bone contains 80% of its original carbon-14

so,

P(t)=0.80Po

we can plug it and then we solve for t

0.80P_0=P_0(\frac{1}{2})^{\frac{t}{5730} }

0.80=(\frac{1}{2})^{\frac{t}{5730} }

\ln \left(0.8\right)=\ln \left(\left(\frac{1}{2}\right)^{\frac{t}{5730}}\right)

t=-\frac{5730\ln \left(0.8\right)}{\ln \left(2\right)}

t=1844.6479

So,

An old bone contains 80% of its original carbon-14 in 1844.6479 years


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