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3 years ago

Solve: 2 3/4 −(−1 1/2 )+(− 5/6 )−(− 3/8)−(+4 2/3 ) PLS HELP!

Mathematics

2 answers:

neonofarm [45]3 years ago

3 0

Answer: -7/8

Step-by-step explanation:

you need to find a common denominator for all of them

in this case it would be 24

2 18/24 -(- 1 12/24) + (-20/24) -(-9/24) - (+ 4 16/24)

2 18/24 + 1 12/24 - 20/24 + 9/24 - 4 16/24

4 6/24 - 20/24 + 9/24 - 4 16/24

3 10/24 + 9/24 - 4 16/24

3 19/24 - 4 16/24

- 21/24

-7/8

makvit [3.9K]3 years ago

3 0

Answer:

-7/8

Step-by-step explanation:

2 18/24 -(- 1 12/24) + (-20/24) -(-9/24) - (+ 4 16/24)

2 18/24 + 1 12/24 - 20/24 + 9/24 - 4 16/24

4 6/24 - 20/24 + 9/24 - 4 16/24

3 10/24 + 9/24 - 4 16/24

3 19/24 - 4 16/24

- 21/24

-7/8

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Consider the following set of data which is plotted on the scatter diagram below

Ivenika [448]

Answer:

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Step-by-step explanation:

8 0

2 years ago

Can someone please help me

Ad libitum [116K]

Square root both sides. The unreduced answer is root 28. Now. To reduce root 28, you need to break it down into factors and hope one of them is a perfect square.

4*7=28, and 4 is a square number. The square root of 4 is either positive or negative 2. Now that you've found that square, pull it out from under the square root symbol. Under the root symbol, you're left with 7 (not a perfect square).

Therefore, your answer is C

7 0

3 years ago

Read 2 more answers

Someone help me with this geometry homework !!!!!! 10 points!

Reil [10]

Answer: 3a = (0, 1) 3b = (2, 1) 3c = (2.5, 1) 3d = (1.6, 1)

4a = (2, 3.5) 4b = (2, 3) 4c = (2, 5.375)

<u>Step-by-step explanation:</u>

The length of AB is 6 and is horizontal (affects the x-coordinate)

$3a)\quad 6\bigg(\dfrac{1}{2}\bigg)\quad =3\qquad \qquad A(-2, 1) +(3, 0)= C(1,1)\\\\\\3b)\quad 6\bigg(\dfrac{2}{3}\bigg)\quad =4\qquad \qquad A(-2, 1) +(4,0)= C(2,1)\\\\\\3c)\quad 6\bigg(\dfrac{3}{4}\bigg)\quad =\dfrac{9}{2}\qquad \qquad A(-2, 1) +(4.5,0)= C(2.5,1)$

$3d)\quad 6\bigg(\dfrac{3}{5}\bigg)\quad =\dfrac{18}{5}\qquad \qquad A(-2, 1) +(3.6,0)= C(1.6,1)$

***********************************************************************************

The length of AB is 5 and is vertical (affects the y-coordinate)

$4a)\quad 5\bigg(\dfrac{1}{2}\bigg)\quad =\dfrac{5}{2}\qquad \qquad A(2, 1) +(0,2.5)= C(2,3.5)\\\\\\4b)\quad 5\bigg(\dfrac{2}{5}\bigg)\quad =2\qquad \qquad A(2, 1) +(0,2)= C(2,3)\\\\\\4c)\quad 5\bigg(\dfrac{7}{8}\bigg)\quad =\dfrac{35}{8}\qquad \qquad A(2, 1) +(0,4.375)= C(2,5.375)$