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nalin [4]
2 years ago
8

Join all the vertices of a regular nonagon to its center. How many identical triangles are formed?

Mathematics
1 answer:
finlep [7]2 years ago
3 0

Answer:

9

Step-by-step explanation:

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Determine whether the given measures can be the lengths of the sides of a triangle. write yes or no. explain. 9.2, 14.5, 17.1
Sergio039 [100]
If the triangle has a angle of 90°, you can solved this exercise by applying the Pythagorean Theorem, which is:

 h²=a²+b²
 h=√(a²+b²)

 h: It is the hypotenuse (The opposite side of the right angle and the longest side of the triangle).

 a and b: They are the legs (The sides that form the right angle).

 The result of h=√(a²+b²), should be 17.1 (The longest side given in the problem). So, let's substitute the values of the legs into the Pythagorean equation:

 h=√(a²+b²)
 h=√((9.2)²+(14.5)²)
 h=17.1

 Therefore, the answer is:

 Yes, the given measures can be the lengths of the sides of a triangle.
3 0
3 years ago
Read 2 more answers
Help please!!<br> 1. What is the value of n?<br> 2.What is the value of n?
lana66690 [7]

Using the intersecting chord theorem:

15 x 2 = 5 x n

Simplify:

30 = 5n

Divide both sides by 5:

n = 30/5

n = 6 m



8 x n+8 = 16 x n+2

Simplify:

8n +64 = 16n +32

Subtract 8n from both sides:

64 = 8n +32

Subtract 32 from both sides:

32 = 8n

Divide both sides by 8:

n = 32 /8

n = 4

4 0
3 years ago
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You must design a closed rectangular box of width w, length l and height h, whose volume is 504 cm3. The sides of the box cost 3
Charra [1.4K]

Answer:

Dimensions will be

Length = 7.23 cm

Width = 7.23 cm

Height = 9.64 cm

Step-by-step explanation:

A closed box has length = l cm

width of the box = w cm

height of the box = h cm

Volume of the rectangular box = lwh

504 = lwh

h=\frac{504}{lw}

Sides which involve length and width and height, cost = 3 cents per cm²

Top and bottom of the box costs = 4 cents per cm²

Cost of the sides C_{s}= 3[2(l + w)h] = 6(l + w)h

C_{s}= 3[2(l + w)h]

C_{s}=6(l+w)(\frac{504}{lw} )

Cost of the top and the bottom C_{(t,p)}= 4(2lw) = 8lw

Total cost of the box C = 3024\frac{(l+w)}{lw} + 8lw

                                      = 3024[\frac{1}{l}+\frac{1}{w}] + 8lw

To minimize the cost of the sides

\frac{dC}{dl}=3024(-l^{-2}+0)+8w=0

\frac{3024}{l^{2}}=8w

\frac{378}{l^{2}}=w ---------(1)

\frac{dC}{dw}=3024(-w^{-2})+8l=0

\frac{3024}{w^{2}}=8l

\frac{378}{w^{2}}=l

w^{2}=\frac{378}{l}-------(2)

Now place the value of w from equation (1) to equation (2)

(\frac{378}{l^{2}})^{2}=\frac{378}{l}

\frac{(378)^{2} }{l^{4}}=\frac{378}{l}

l³ = 378

l = ∛378 = 7.23 cm

From equation (2)

w^{2}=\frac{378}{7.23}

w^{2}=52.28

w = 7.23 cm

As lwh = 504 cm³

(7.23)²h = 504

h=\frac{504}{(7.23)^{2}}

h = 9.64 cm                        

6 0
4 years ago
It took 5 people to clean a classroom in 4 hours. How long would it take 4 people? Please help
SpyIntel [72]

Answer:

3 hours, duh

Step-by-step explanation:

8 0
3 years ago
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The price of an item decreased by 20% to $200. Then later the price decreased again from $200 to $150. What is the percent of de
cricket20 [7]

Answer:

40%

Step-by-step explanation:

ok so first find the og price:

100% - 20% = 80%

so 80% = 200

let the 100% be x:

x * 0.8 = 200

x= 250

100% = 250

(difference/ og price) * 100% = the percentage decrease/ increase

(250-150/250)* 100% = 40%

OR

((the final price/ og price) * 100%) - 100%

((150/250)*100%) - 100% = 40%

There was a 40% decrease from the og price to the final price of 150.

3 0
3 years ago
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