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nalin [4]
2 years ago
8

Join all the vertices of a regular nonagon to its center. How many identical triangles are formed?

Mathematics
1 answer:
finlep [7]2 years ago
3 0

Answer:

9

Step-by-step explanation:

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Help no time plzzzz plz plz​
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FALSE

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<E in ∆AED ≅ <E in ∆CEB.

Both are 90°.

Side ED ≅ Side EB

Side AD ≅ Side CB.

Thus, two sides (ED and AD) and a non-included angle (<E) of ∆AED are congruent to corresponding two sides (EB and CB) and a non-included angle (<E) of ∆CEB. Therefore, by A-S-S Congruence Theorem, both triangles are congruent to each other not by SSS.

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Find x, and then any unknown angles in the quadrilateral.<br> x= ?
sertanlavr [38]

Answer:

x=65

other angle= 165

Step-by-step explanation:

quadrilaterals always have a total of 360 degrees

because of this you can set up an equation and solve

360=90+40+x+(4x-95)

360=130+5x-95

360=35+5x

325=5x

65=x

plug this in to find missing angle

4(65)-95=165

7 0
3 years ago
The lines y=3x-1 and y=ax+2 are perpendicular if a=___
mezya [45]

Answer:

a = \frac{-1}{3}.

Step-by-step explanation:

The equation of line in the form .

y = mx + c

Where m is the slope and c is the y- intercept .

As given

The lines y=3x-1 and y=ax+2 are perpendicular .

Here 3 is slope for equation of line  y=3x-1 and a is slope for equation of line

y=ax+2 .

Now by using properties of the perpendicular lines property .

When two lines are perpendicular than slope of one line is negative reciprocal of the other line .

Thus

a = \frac{-1}{3}

Therefore a = \frac{-1}{3}.

8 0
3 years ago
Read 2 more answers
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