Help me plz this due tommorow and i need help with this

Quadrilateral ABCDABCD has vertices AA (-2, 2), BB (4, 5), CC (3, 0) and DD (-3, -3). What are the coordinates of the midpoint o

Arada [10]

Check the picture below.

the quadrilateral is a parallelogram, thus the diagonals bisect each other, so, we could have used either diagonal, and get the same midpoint.

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
B&({{ 4}}\quad ,&{{ 5}})\quad 
% (c,d)
D&({{ -3}}\quad ,&{{ -3}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ -3+4}} }{2}\quad ,\quad \cfrac{-3+5}{2} \right)$

6 0

4 years ago

The deterioration of many municipal pipeline networks across the country is a growing concern. One technology proposed for pipel

otez555 [7]

Answer:

The calculated value of t= -0.21 does not lie in the critical region t= ± 2.120 Therefore we accept our null hypothesis that there's no difference between strength (psi) of liner specimens when a certain fusion process was used and when this process was not used at the 0.05 significance level

Step-by-step explanation:

The given data is

No Fusion :: 2748 2700 2655 2822 2511 3149 3257 3213 3220 2753

Yes Fusion :: 3027 3356 3359 3297 3125 2910 2889 2902

The calculated Means are

x1`= 2902.8

X2`= 3108.125

The standard deviations are

s1= 277.265

s2= 205.87

We are using Student's t- test

We formulate null and alternate hypotheses are

H0 : u1 - u2= 0 against Ha: u1 - u 2≠0

The Significance level alpha is chosen to be ∝ = 0.05

The critical region t ≥ t (0.025, 16) = ± 2.120

Degrees of freedom is calculated df = υ= n1+n2- 2= 10+8-2= 16

Here the difference between the sample means is x`1- x`2

=2902.8-3108.125

= -205.325

The pooled estimate for the common variance σ² is

Sp² = (n1-1) s1² + (n2-1) s2²/ n1+n2-2

= 9( 277.265)² + 7(3108.125)²/ 16

Sp² = 691,882.922+67,623,087.109/16

Sp= 2066.321

The test statistic is

t = (x`1- x` ) /. Sp √1/n1 + 1/n2

t= -205.325/ 2066.321 √1/10+ 1/8

t= -205.325/980.142

t= -0.2095= -0.21

Conclusion

The calculated value of t= -0.21 does not lie in the critical region t= ± 2.120 Therefore we accept our null hypothesis that there's no difference between strength (psi) of liner specimens when a certain fusion process was used and when this process was not used at the 0.05 significance level

5 0

3 years ago

A food company sells salmon to various customers. The mean weight of the salmon is 37 lb with a standard deviation of 2 lbs. The

brilliants [131]

Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

$\overline{X} = \frac{X_1+X_2+...+X_n}{n}$

If $X_1, ..., X_n$ are indentically distributed and independent, like in the situation of the problem, then the variance of $X_1 + .... + X_n$ will be the sum of the variances, in other words, it will be n times the variance of $X_1$ .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus $\overkine{X} = \frac{V(X_1)}{n}$ and as a result, the standard deviation of $\overline{X}$ is the standard deviation of $X_1$ divided by $\sqrt{n}$ .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

Restaurants: We have boxes with 9 salmon each, so it will be $\frac{2}{\sqrt{9}} = \frac{2}{3}$
Grocery stores: Each carton has 49 salmon, thus the standard deviation is $\frac{2}{\sqrt{49}} = \frac{2}{7}$
Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is $\frac{2}{\sqrt{64}} = \frac{1}{4}$

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

7 0

3 years ago

Write down the integer values satisfied by the diagram

____ [38]

Answer: