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Answer:
The assumption is quite reasonable.........
A lightbulb contains Ar gas at a temperature of 295K and at a pressure of 75kPa. The light bulb is switched on, and after 30 minutes its temperature is 418 K. What is a numerical setup for calculating the pressure of the gas inside the light bulb at 418K?
Explanation:
P
1
T
1
=
P
2
T
2
given constant
n
, and constant
V
, conditions that certainly obtain with a fixed volume light bulb.
And so
P
2
=
P
1
T
1
×
T
2
=
75
⋅
k
P
a
295
⋅
K
×
418
⋅
K
≅
100
⋅
k
P
a
.
Had the light bulb been sealed at normal pressure during its manufacture, what do you think might occur when it is operated?
Answer:
The answer to your question is: 79.6 L
Explanation:
Data:
n = 60 moles
Pressure = P = 20.0 atm
Temperature = T = 50°C
Volume = V = ?
Convert temperature to Kelvin
°K = 273 + 50
°K = 323
Formula (ideal gas law)
PV = nRT solve for V
V = nRT / P
V = (60)(0.08206)(323) / 20 Substitution
V = 1590.32 /20
V = 79.6 L
A roller coaster reaches its maximum P.E when it is at the top ;)
10.155.151 this is the answer
