Answer:
187,726.85 and 630,726.85
Answer:
The number of moles of water will be produced when 8.0 moles of ethane are burned = 24.0 mol.
Explanation:
- It is a stichiometry problem.
- The balanced equation of burning ethane is:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
- It is clear that 2.0 moles of ethane (C₂H₆) burns in 7.0 moles of oxygen and produce 4.0 moles of CO₂ and 6.0 moles of H₂O.
<em><u>Using cross multiplication:</u></em>
2.0 moles of ethane produces → 6.0 moles of H₂O, from the stichiometry.
8.0 moles of ethane produces → ??? moles of H₂O.
- ∴ The number of moles of water will be produced when 8.0 moles of ethane are burned = (6.0 x 8.0) / (2.0) = 24.0 mol.
Mg is what you measure them in
Answer:
0.5M
Explanation:
The equation for molarity is:
- M =
; where the "M" stands for molarity, the "mol" stands for moles of solute and the "liters" means the volume in liters of solution.
We are given that there are:
- 1.80 moles of NaCl (the moles of solute)
- 3.60 Liters of solution (the volume in liters of solution)
Now we just plug those numbers into the formula and get our answer:
- M=
= 0.5M
After doing the math and dividing the moles of solute by the liters of solution, we get that the molarity of the solution is 0.5M.
The best way to separate out a precipitate is using vacuum filtration. Use water to rinse out the flask thoroughly and wash the precipitate, followed by a quick rinse with ethanol to help dry it. After a few minutes on the vacuum pump, the precipitate should be ready to scrape off.<span> Also, centrifugation can be an option for small amounts especially if you just need the filtrate. For reasonable amounts, a Millipore setup or Gooch type crucible works nicely for quantitative analysis.</span>
