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ikadub [295]
1 year ago
8

SeF6 1. Lewis Structure 2. Perspective drawing 3. Number of atoms bonded to central atom 4. Number of non-bonding electron pairs

on the central atom 5. Electronic geometry: 6. Molecular geometry with ideal bond angles 7. Hybridization of central atom 8. Polarity:
Chemistry
1 answer:
Anarel [89]1 year ago
7 0

The answer is- SF_{6} is octahedral in electronic and molecular geometry with 6 Fluorine atoms bonded to central atom S.

Lewis structures are the diagrams in which the valence electrons of the atoms of a compound are arranged around the atoms showing the bonding between the atom and the lone pair of electrons existing in the molecule.

Determine the molecular geometry of SF_{6}.

  • Valence Shell Electron Pair Repulsion theory is commonly known as VSEPR theory and it helps to predict the geometry of molecules.
  • According to this theory, electrons are arranged around the central atom of the molecule in such a way that there is minimum electrostatic repulsion between these electrons.
  • Now, calculate the total number of valence electrons in SF_{6}.

Valence\ electrons\ in\ SF_{6}= Valence\ electrons\ in\ S +\ 6(Valence\ electrons\ in\ F)

Valence electrons of S = 6

Valence electrons of F = 7

Thus, the valence electrons in SF_{6} are-

Valence\ number\ of\ electrons\ in\ SF_{6} = (6) + 6(7) = 48\ electrons.

  • The Lewis structure of SF_{6} is - (Image attached).
  • In the structure, the number of atoms bonded to central atom (S) = 6.
  • Number of non-bonding electron pairs on the central atom = 0 (as all the valence electrons are bonded to F).
  • Electronic geometry in case of 6 bond pairs is octahedral.
  • Molecular geometry us also octahedral with bond angles 90°.
  • Central atom is sp3d2 hybridised.
  • SF_{6} is a non-polar molecule.

To learn more about Lewis structures visit:

brainly.com/question/12307841?referrer=searchResults

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quizlet a basement is successfully sealed so that more radon may not enter the space, but 5.7×107 radon atoms are already trappe
12345 [234]

After 25 days, it remains radon 5.9x10^5 atoms.

Half-life is the time required for a quantity (in this example number of radioactive radon) to reduce to half its initial value.

N(Ra) = 5.7×10^7; initial number of radon atoms

t1/2(Ra) = 3.8 days; the half-life of the radon is 3.8 days

n = 25 days / 3.8 days

n = 6.58; number of half-lifes of radon

N1(Ra) = N(Ra) x (1/2)^n

N1(Ra) = 5.7×10^7 x (1/2)^6.58

N1(Ra) = 5.9x10^5; number of radon atoms after 25 days

The half-life is independent of initial concentration (size of the sample).

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6 0
2 years ago
The volume of a gas is 6.10 l, measured at 1.50 atm. what is the pressure of the gas in
Volgvan

Answer:

713.96mmhg

Explanation:

p1v1=p2v2

6.10×1.50/9.74

=0.939atm

=0.939*760

=713.96mmhg

5 0
2 years ago
Which group of lists below is made up of only pure substances?
german

Answer:

the answer is compounds

5 0
2 years ago
Na2SO3" represents sodium sulfite. What does the 4 mean in the formula 4Na2SO3? There are four atoms of sodium. There are four a
coldgirl [10]

The designation "4" before Na2SO3 simply means that there are four molecules of sodium sulfite.

A molecule is formed when two or more atoms of the same or different elements come together. The formula of the molecule must reflect the number of atoms from which it is formed. The designation "4" before Na2SO3 simply means that there are four molecules of sodium sulfite.

The "The World on Turtle's Back" is a legend creation story. According to this story, the world was created on a giant turtle back. The folktale is common among the  Iroquois Native Americans.

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7 0
2 years ago
a certain piece of copper wire is determined to have a mass of 2.0 0g per meter how many centimeters of the wire would be needed
harina [27]

The given question tells you that a certain piece of wire has a mass  = 2.0 g per meter

That means that if you consider a piece of wire that is 1 m in length, its mass will be equal to  2.00 g .

According to question,

Now, you know that

1 m = 100 cm

Mass of  2.00 g  of copper will correspond to a wire that is a 100 cm long.

This implies that  0.28 gof copper will correspond to a wire that is

0.28 g * 100 cm /  2.0 g = 14 cm long

Hence, 14 cm of the wire would be needed to provide 0.28 g of copper.

Properties of Copper :

High conductivity and ductility.

Non magnetic.

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3 0
2 years ago
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