Answer:
the first three are the answer
Step-by-step explanation:
The first step would be D
Answer:
11.33 in. to the nearest hundredth.
Step-by-step explanation:
The perimeter of the shaded area = length of the 2 straight lines + the length of the 2 arcs = 4 + length of the 2 arcs.
Calculate the length of the outer arc:
This equals (30 / 360) * perimeter of the largest circle
= 1/12 * 2 π * 8
= 4/3 π in.
The inner circle has a radius of 8 - 2 = 6 ins
so the length of the inner arc
= 1/12 * π * 2 * 6
= π in.
So the perimeter of the shaded region = 4 + 4/3 π + π
= 4 + 7π/3
= 11.33 in.
Answer:
Answer:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
Where xx is the number of small boxes sent and yy is the number of large boxes sent.
Step-by-step explanation:
Let be xx the number of small boxes sent and yy the number of large boxes sent.
Since each small box can hold 20 books (20x20x ), each large box can hold 30 books (30y30y )and altogether can hold a total of 280 books, we can write the following equation to represent this:
20x+30y=28020x+30y=280
According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:
y=4xy=4x
Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.