Answer:
54 J
Explanation:
Kinetic energy is:
KE = 1/2 mv²
where m is mass and v is velocity.
Given m = 3 kg and v = 6 m/s:
KE = 1/2 (3 kg) (6 m/s)²
KE = 54 J
Answer:
frequency =speed/wavelength
=(3*10^8)/150
=2×10^6
Answer:
The minimum distance is ![y = 892.48 \ cm](https://tex.z-dn.net/?f=y%20%20%3D%20892.48%20%5C%20cm)
Explanation:
The diagram of this set up is shown on the first uploaded image
From the question we are told that
The wavelength is ![\lambda = 9.00\ cm](https://tex.z-dn.net/?f=%5Clambda%20%3D%209.00%5C%20cm)
The width of the slit is ![d = 12.0 cm](https://tex.z-dn.net/?f=d%20%3D%20%2012.0%20cm)
The distance of the microphone is ![L = 8.0 \ m = 8*100 = 800 \ cm](https://tex.z-dn.net/?f=L%20%20%3D%20%208.0%20%5C%20m%20%20%3D%20%208%2A100%20%3D%20%20800%20%5C%20cm)
Generally the diffraction minima in a single slit is mathematically represented as
Where m is the order of diffraction which is 1 in this question
So making
the subject
![\theta = sin^{-1} [\frac{m * \lambda }{ d} ]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%20sin%5E%7B-1%7D%20%5B%5Cfrac%7Bm%20%2A%20%5Clambda%20%7D%7B%20d%7D%20%5D)
![\theta = sin^{-1} [\frac{1 * 9.00}{12.00} ]](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%20sin%5E%7B-1%7D%20%5B%5Cfrac%7B1%20%2A%209.00%7D%7B12.00%7D%20%5D)
![\theta =0.84 \ rad](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D0.84%20%20%5C%20%20rad)
Now from the diagram
![y = 800 tan 0.84](https://tex.z-dn.net/?f=y%20%20%3D%20800%20tan%200.84)
![y = 800* (1.1156)](https://tex.z-dn.net/?f=y%20%20%3D%20800%2A%20%20%281.1156%29)
![y = 892.48 \ cm](https://tex.z-dn.net/?f=y%20%20%3D%20892.48%20%5C%20cm)
Answer:
The value is ![E = 8.9 *10^{-5} \ J](https://tex.z-dn.net/?f=E%20%3D%20%208.9%20%2A10%5E%7B-5%7D%20%5C%20%20J)
Explanation:
From the question we are told that
The area is ![A = 0.700 \ m^2](https://tex.z-dn.net/?f=A%20%3D%20%200.700%20%5C%20%20m%5E2)
The root mean square value is ![E_{rms} = 0.0400 \ V/m](https://tex.z-dn.net/?f=E_%7Brms%7D%20%3D%20%200.0400%20%5C%20%20V%2Fm)
The time taken is ![t = 30.0 \ s](https://tex.z-dn.net/?f=t%20%3D%20%2030.0%20%5C%20%20s)
Generally the energy is mathematically represented as
![E = c * \sepsilon_o * A * t * E_{rms}^2](https://tex.z-dn.net/?f=E%20%3D%20%20c%20%2A%20%20%5Csepsilon_o%20%2A%20%20A%20%20%2A%20%20t%20%20%2A%20E_%7Brms%7D%5E2)
=> ![E = 3.0*10^{8} * 8.85*10^{-12} * 0.700 * 30 * (0.04)^2](https://tex.z-dn.net/?f=E%20%3D%20%203.0%2A10%5E%7B8%7D%20%2A%20%208.85%2A10%5E%7B-12%7D%20%2A%20%200.700%20%2A%20%2030%20%2A%20%280.04%29%5E2)
=> ![E = 8.9 *10^{-5} \ J](https://tex.z-dn.net/?f=E%20%3D%20%208.9%20%2A10%5E%7B-5%7D%20%5C%20%20J)