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2 years ago

14

Someone plz give me some boy advice I really need it.

1 answer:

Tanya [424]2 years ago

8 0

If your wanting to know how to talk to them, just act like you know them really well be very causal and be confident in what you say, they also like it when you make the first move to talk to them

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Which is one way scientists indicate how precise and accurate there experimental measurements are

kherson [118]

They do the method 3 times to be sure. Because if you do it once, that could mean anything. If you do it twice, it may or may not have the same result. If you do it 3 times and it matches one of the previous answers, then it's likely that it's correct.

8 0

3 years ago

Which of the materials would be able to scratch Quartz

Lelechka [254]

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3 years ago

Which type of heat transfer causes your face to feel warm when you sit in the sun?

MA_775_DIABLO [31]

Answer:

Radiation

Explanation:

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6 0

3 years ago

Two identical loudspeakers are placed on a wall 1.00 m apart. A listener stands 4.00 m from the wall directly in front of one of

natita [175]

Answer:

The phase difference is 0.659 rad.

Explanation:

Given that,

Distance between two identical loudspeakers d= 1.00 m

Distance between speakers and listener r= 4.00 m

Frequency = 300 Hz

Suppose we need to find the phase difference in radian between the waves from the speakers when they reach the observer

We need to calculate the r'

Using Pythagorean theorem

$r'=\sqrt{d^2+r^2}$

Where, d = distance between two identical loudspeakers

r = distance between speakers and listener

Put the value into the formula

$r'=\sqrt{(1.00)^2+(4.00)^2}$

$r'=\sqrt{1.00+16.00}$

$r'=4.12\ m$

We need to calculate the path difference

Using formula of path difference

$|r'-r|=4.12-4.00$

$|r'-r|=0.12\ m$

We need to calculate the wavelength

Using formula of wavelength

$\lambda=\dfrac{v}{f}$

Where, v = speed of sound

f = frequency

Put the value into the formula

$\lambda=\dfrac{343}{300}$

$\lambda=1.143\ m$

We need to calculate the phase difference

Using formula of phase difference

$\phi=\dfrac{2\pi\times|r'-r| }{\lambda}$

$\phi=\dfrac{2\pi\times0.12}{1.143}$

$\phi=0.659\ rad$

Hence, The phase difference is 0.659 rad.

7 0

3 years ago

in the system to the right, the pulleys are frictionless and the system hangs in equilibrium. Determine the values of each of th

irga5000 [103]

Look up pulleys problem through Khan academy and a video should pop up with a problem similar and you should be able to walk through it .

4 0

3 years ago