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Serga [27]
3 years ago
6

Two wires, each of length 1.2m are stretched between 2 fixed supports. On wire A there is a second harmonic standing wave whose

frequency is 660 Hz. However, the same frequency, 660 Hz, is the third harmonic for wire B. Find the speed at which the waves travel on each wire.

Physics
1 answer:
emmainna [20.7K]3 years ago
4 0

Explanation:

Below is an attachment containing the solution

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Three parallel wires each carry current I in the directions shown in (Figure 1). The separation between adjacent wires is d.
jasenka [17]

(a) The magnitude of the net magnetic force per unit length on the top wire is μI²/πd.

(b) The magnitude of the net magnetic force per unit length on the middle wire is zero.

(c) The magnitude of the net magnetic force per unit length on the bottom wire is 3μI²/4πd.

<h3>Force per unit length</h3>

The magnitude of the net magnetic force per unit length on the top wire is calculated as follows;

F₁/L = (μI₁/2π) x (I₂/d + I₃/d)

F₁/L = (μI/2π) x (I/d + I/d)

F₁/L = (μI/2π) x (2I/d)

F₁/L = μI²/πd

The magnitude of the net magnetic force per unit length on the middle wire is calculated as follows;

F₂/L = (μI₂/2π) x (I₃/d - I₁/d)

F₂/L = (μI/2π) x (I/d -  I/d) = 0

The magnitude of the net magnetic force per unit length on the middle bottom is calculated as follows;

F₃/L = (μI₂/2π) x (I₁/d + I₂/d)

F₃/L =  (μI/2π) x (I/2d + I/d)

F₃/L =  (μI/2π) x (3I/2d)

F₃/L =  3μI²/4πd

Thus, the magnitude of the net magnetic force per unit length on the top wire is μI²/πd.

The magnitude of the net magnetic force per unit length on the middle wire is zero.

The magnitude of the net magnetic force per unit length on the bottom wire is 3μI²/4πd.

Learn more about magnetic force here: brainly.com/question/13277365

#SPJ1

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a 5kg block on a rough horizontal surface is attached to a light spring (force constant=1.6kN/m). the block passes through its e
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Answer:

2.12 J

Explanation:

Initial kinetic energy = final elastic energy + work by friction

KE = EE + W

KE = ½ kx² + W

5 J = ½ (1600 N/m) (0.06 m)² + W

W = 2.12 J

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If a car traveled 60 m in 30 s, what is the velocity?*
klemol [59]

Answer:

6.56168

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Why would a flat sheet of paper and a wad of paper not fall through the air at the same rate
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There mass is a different size (weight)
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