Answer:
So the minimum force is
32.2Newton
Explanation:
To solve for the minimum force, let us assume it to be F (N)
So
F=mgsinA
But
=>>>> coefficient of static friction x (F + mgcosA
=>3 x 9.8 x sin35 = 0.3 x (F + 3 x 9.8 x cos35)
So making F subject of formula
F + 24.0 = 56.2
F = 32.2N
Answer:
v = 29.4m/s
Explanation:
Since the ball is dropped at rest,
u = 0m/s
a = 9.81m/s²
Using
v = u + at
After 3 seconds,
v = 0 + (9.81)(3)
v = 29.4m/s
Answer: D!
It is the option with the greatest amplitude.
1. b
2. c
3. a
4. a
5. b
6. should be 2400? unless u put the wrong numbers, it is probably 240 then
here we know that the speed of the signal is same as the speed of light
so here we will have

the altitude of the airplane is given as

now we know that time taken by the signal to reach the control tower is given as

now it is given as


so above is the time taken by the signal to reach the control tower