Answer:
W = 3.21x10⁻¹¹ J
Explanation:
The work required to separate the plates can be calculated using the following equation:
<u>Where</u>:
U₂: is the final stored energy
U₁: is the initial stored energy
C₂: is the final capacitance
C₁: is the initial capacitance
V₁: is the initial potential difference = 5.00 V
V₂: is the final potential difference
The initial and final capacitance is:
<u>Where</u>:
ε₀: is the vacuum permittivity = 8.85x10⁻¹² C²/(N*m²)
d: is the initial distance = 3.00 mm = 3.00x10⁻³ m
A: is the plate area = 865 mm² = 8.65x10⁻⁴ m²
Similarly, C₂ is:
Now, V₂ can be calculated by finding the initial charge (q₁):
Since, q₁ is equal to q₂, V₂ is:
Finally, we can find the work:
Therefore, the work required to separate the plates is 3.21x10⁻¹¹ J.
I hope it helps you!