Answer:
f1 = 58.3Hz, f2 = 175Hz, f3 = 291.6Hz
Explanation:
lets assume speed of sound is 350 m/s.
frequencies of a standing wave modes of an open-close tube of length L
fm = m(v/4L)
where m is 1,3,5,7......
and fm = mf1
where f1 = fundamental frequency
so therefore: f1 = 350 x 4 / 1.5
f1 = 58.3Hz
f2 = 3 x 58.3
f2 = 175Hz
f3 = 5 x 58.3
f3 = 291.6Hz
Data:
mass, m = 30.94 g
density, d = 19.32 g/cm^3
Formula: d = m / v => v = m / d = 30.94 g / 19.32 g/cm^3 = 1.60 cm^3
Then, the answer is the option C.
Answer:
<u>954.4m/s</u>
Explanation:
For a free falling object,it has constant acceleration and a changing velocity.
By using the velocity-time formula, the velocity can be obtained.
The height the rock travelled is the distance.
From,
Velocity (v) = Distance (d) / Time(t)
v = 3245m/3.4s
v = <u>954.4m/s</u>
That js the answer I got. Hope it's right.
Answer:
A:7.2
B:14.25
C:1.45
D:10.3
E:2.9
F:20.88
Explanation:
Let 
be the velocity and 
be the angle between the velocity and ground.
Question A:
Horizontal component of velocity is given by 
.
So,horizontal component is 
Question B:
Vertical component of velocity is given by 
.
So,vertical component is 
Question C:
Time required is given by 
Question D:
Maximum height is given by 
Question E:
Time of flight is twice the time required to reach maximum height=
.
Question F:
The distance between the player and ball after landing is called range and is given by 
