I don't think anyone can read that, sorry!
Answer:
a) There are 8 possible combinations and each probability is 1/8.
b) The probability that it is a boy given that there are two girls is 3/8
Step-by-step explanation:
a) The sample space is given by:
BBB (3 boys)
BBG (Boy, boy, girl)
BGB (Boy, girl, boy)
BGG (Boy, girl, girl)
GBB (girl, boy, boy)
GBG (girl, boy, girl)
GGB (girl, girl, boy)
GGG (3 girls)
The probability of each combination is the same:
P(BBB)=P(B∩B∩B)=
2) There are three possible combinations in which there are 2 girls and 1 boy:
BGG, GBG, GGB
So the probability is given by:
P(BGG ∪ GBG ∪ GGB)=
Answer: when x =0
Step-by-step explanation:
Y=3(0)+1
0+1
1
Combining the fractions gives

Since
, we also have


If we add and subtract the last 7 terms of the left hand side to/from the numerator, we get



Also because
, we have

so we find that

Answer:
x = 2
Step-by-step explanation:
Using Pythagoras identity in the right triangle
x² = 10² + 6² = 100 + 36 = 136 ( take the square root of both sides )
x =
=
= 2