Force=(mass*velocity)-(mass*velocity)/time
force=0-(-15*1400)/0.30
force=70000N
Answer:
Kindly check the explanation section.
Explanation:
For the design we are asked for in this question/problem there is the need for us to calculate or determine the strength in fracture and that of the yield. Also, we need to calculate for the block shear strength.
From the question, we have that the factored load = 500kips. Also, note that the tension splice must not slip.
Also, the shear force are resisted by friction, that is to say shear resistance = 1.13 × Tb × Ns.
Assuming our db = 3/4 inches, then the slip critical resistance to shear service load = 18ksi(refer to AISC manual for the table).
If db = 7/8 inches, then the shear force resistance for n bolt = 10.2kips, n > 49.6.
The yielding strength = 0.9 × Aj × Fhb= 736 kips > 500
The fracture strength = .75 × Ah × Fhb = 309 kips.
The bearing strength of 7/8 inches bolt at the edge hole and other holes = 46 kips and 102 kips.
First, calculate for the distance between the given points A and B by using the equation,
<span> D = sqrt ((x2 – x1)2 + (y2 – y1)2)</span>
Substitute the known values:
<span> D = sqrt((9 – 2)2 + (25 – 1)2)</span>
<span> D = 25 m</span>
I assume the unknown here is the time it would require for the particle to move from point A to B. This can be answered by dividing the calculated distance by the speed given above.
<span> t = (25 m)/ (50 m/s) = 0.5 s</span>
<span>Thus, it will take 0.5s for the particle to complete the route. </span>
Answer:
50.96 N
Explanation:
weight = mass x gravity
We know that gravity = 9.8 m/s^2 and mass = 5.2 kg.
w = m x g
w = 5.2 kg x 9.8 m/s^2
w = 50.96 N
The weight of the object is 50.96 N (newtons). Hope this helps, thank you !!
Answer: If mass remains constant and you double the force you will double the acceleration.