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3 years ago

Which inequality represents that 18 less than twice a number more than 35?

Mathematics

1 answer:

Len [333]3 years ago

3 0

Answer:

B. 2n - 17 < 35

Hope it helps you:)

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Below are the results of tossing a number cube 9 times. Find the experimental probability of tossing an odd number. 4, 3, 6, 6,

My name is Ann [436]

Answer: C. $\dfrac{5}{9}$

Step-by-step explanation:

Given: The results of tossing a number cube 9 times are:

4, 3, 6, 6, 2, 5, 3, 5, 1

Then , the number of times get odd number (3,5,3,5,1): 5

Now, the experimental probability of tossing an odd number will be :

$\text{P(odd)}=\dfrac{\text{Number odd results}}{\text{Total number of times coin tossed}}\\\\\Rightarrow\ \text{P(odd)}=\dfrac{5}{9}$

Hence, the experimental probability of tossing an odd number $\dfrac{5}{9}$

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4 years ago

What is the slope of the line that passes through the points given in the table? ANSWER IN DECIMAL FORM

PolarNik [594]

Answer:

1.5

Step-by-step explanation:

the slope formula is y2-y1/x2-x1

so take two given points (I'll use (-1, -5) and (3,1))

1--5/3--1

6/4

1 2/4

1.5

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3 years ago

A salesperson ratio of successful signups to the number of people called is .125. This month, the salesperson has 25 signups.

morpeh [17]

For every 8 people called, one signs up. So, for 25 signups you get 25*8=200 called people.

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3 years ago

If 12 people are to be divided into 3 committees of respective sizes 3, 4, and 5, how many divisions are possible?

Reil [10]

Answer: 1320

Step-by-step explanation:

I think this is a permutation problem

n p r = n! / (n-r)!

12 P 3 = 12! / (12-3)!

= 12! / 9!

= 12× 11 ×10 × 9! / 9!

The 9! in the numerator and denminator will cancel out

12 P 3 = 12 × 11 × 10 = 1320

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3 years ago

The regular hexagon ABCDEF rotates 240º counterclockwise about its center to form hexagon A′B′C′D′E′F′. Point C′ of the image co

const2013 [10]

<span>The regular hexagon ABCDEF rotates 240º counterclockwise about its center to form hexagon A′B′C′D′E′F′. Point C′ of the image coincides with point _E_ of the preimage. Point D′ of the image coincides with point _F_ of the preimage.</span>

5 0

4 years ago

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