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MrMuchimi
3 years ago
8

Word Bank: Mixtures, Compounds, Matter, Homogeneous, Element, Substance, Heterogeneous

Chemistry
1 answer:
docker41 [41]3 years ago
4 0

Answer:

<em>1</em><em>.</em><em> </em><em>Element</em>

<em>2</em><em>.</em><em> </em><em>Heterogeneous</em><em> mixture</em>

<em>3</em><em>.</em><em> </em><em> </em><em>Compound</em>

<em>4</em><em>.</em><em> </em><em>Mixture</em><em> </em><em>or </em><em>Substances</em>

<em>5</em><em>.</em><em> </em><em>Elements</em>

<em>6</em><em>.</em><em> </em><em>Homogeneous</em><em> mixture</em>

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How many grams of krypton gas will occupy 2.55 liters at 1.25 atm if it occupies 3.75 liters at 0.750 atm at 255 K
tatiyna

Answer:

There will be 94.7 grams of krypton gas

Explanation:

<u>Step 1:</u> Data given

at 255K and 0.750 atm the volume is 3.75 L

At 1.25 atm the volume is 2.55 L

Molar mass of krypton = 83.798 g/mol

<u>Step 2</u>: Calculate number of moles

p*V = n*R*T

with p = the pressure of the krypton gas = 0.750 atm

with V = the volume of the krypton gas = 3.75 L

with n = the number of moles = TO BE DETERMINED

with R = the gasconstant = 0.08206 L*atm/ mol * K

with T = the temperature = 255 K

n = R*T / p*V

n = (0.08206 * 255)/ (0.750 * 3.75)

n = 0.744 moles

<u>Step 3:</u> Calculate new number of moles

P1*V1 = P2*V2

P1*V1 = n1*R*T

P2*V2 = n2*R*T

(P1*V1)/R*T = (P2*V2)/n2*R*T

Since R and T do not change we can write as followed:

(P1*V1) = (P2*V2) /n2

n2 = (P2*V2) / (P1*V1)

n2 = (2.55 *1.25)/(0.75*3.75)

n2 = 1.13 moles

<u>Step 4:</u> Calculate mass of krypton gas

mass = Number of moles * Molar mass

mass of krypton gas = 1.13 moles * 83.798 g/mol = 94.69 grams ≈ 94.7 grams

There will be 94.7 grams of krypton gas

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3 years ago
Cyclohexane (C6H12) undergoes a molecular rearrangement in the presence of AlCl3 to form methylcyclopentane (CH3C5H9) according
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Answer:

The reaction will shift leftwards, towards the formation of more cyclohexane at 25 °C

Explanation:

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In this case, for the given chemical reaction, we can write the law of mass action (equilibrium expression) as shown below:

Kc=\frac{[CH_3C_5H_9]}{[C_6H_{12} ]}

Thus, since Kc < 1, we can conclude there are more moles of cyclohexane at equilibrium (denominator is greater than numerator), therefore, the reaction will shift leftwards, towards the formation of more cyclohexane at 25 °C.

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