All categories

3 years ago

PLEASE HELP ASAP!!!

Chemistry

1 answer:

kipiarov [429]3 years ago

8 0

Answer:

i feel like it's false. i'm not quite sure, but i have a feeling that it's false. i hope i'm right.

Explanation:

You might be interested in

Automobile airbags inflate due to the formation of nitrogen gas from the chemical reaction 2NaN3(s)⟶3N2(g)+2Na(s) Identify the n

Vera_Pavlovna [14]

First part:

2 atoms of Na

6 atoms of N

Second part:

2 atoms of N

2 atoms of Na

Why?

We are given the chemical reaction, so, we can extract the number of atoms for both reactants and products.

We are given the chemical equation:

$2NaN_{3}=3N_{2}+2Na$

We can rewrite it as follow:

$2(NaN_{3})=3N_{2}+2Na$

From the reactants, we have:

$2(NaN_{3})$

$2Na=2atoms\\2N_{3}=2*3=6atoms$

From the products we have:

$3N_{2}+2Na$

$3N_{2}=3*2=6atoms$

$2Na=2atoms$

Hence, we have that:

There are 6 atoms of N in the reactants and 6 atoms of N in the products.

and

There are 2 atoms of Na in the reactants and 2 atoms of Na in the products since we have a balanced equation.

Have a nice day!

6 0

3 years ago

Calculate the ph at the equivalence point for the titration of 0.230 m methylamine (ch3nh2) with 0.230 m hcl. the kb of methylam

Vlad1618 [11]

Answer: The pH at the equivalence point for the titration will be 0.65.

Solution:

Let the concentration of $[OH^-]$ be x

Initial concentration of $[CH3NH_2]$ , c = 0.230 M

$CH_3NH_2+H_2O\rightleftharpoons CH_3NH_3^++OH^-$

at eq'm c-x x x

Expression of $K_b$ :

$K_b=\frac{[CH_3NH_3^+][+OH^-]}{[CH_3NH_2]}=\frac{x\times x}{c-x}=\frac{x^2}{c-x}$

Since ,methyl-amine is a weak base,c>>x so $c-x\approx c$ .

$K_b=\frac{x^2}{c}=5.0\times 10^{-4}=\frac{x^2}{0.230 M}$

Solving for x, we get:

$x=1.07\times 10^{-2} M$

Given, HCl with 0.230 M , it dissociates fully in water which means $[H^+]$ = 0.230 M

$[OH^-]=[H^+]$ will result in neutral solution, since $[OH^-]$

Remaining $[H^+]$ after neutralizing $[OH^-]$ ions

$[H^+]_{\text{left in solution}}=[H^+]-[OH^-]=0.230-1.07\times 10^{-2}=0.2193 M$

$pH=-log{[H^+]_{\text{left in solution}}=-log(0.2193)=0.65$

The pH at the equivalence point for the titration will be 0.65.

8 0

4 years ago

Step 6: Measure Pressure and Volume with the Book and 1 kg of Weight

goldfiish [28.3K]

Answer:

Starting from the top

1.498

1.18

43.5

51.3

For step 7

2.498

1.27

40.5

51.4

For 8

3.498

1.37

37.5

51.4

For 9

4.498

1.47

35.0

51.5

Lmk if anyone needs earlier steps, but I'm going to assume no since you're already on 6

Explanation:

7 0

3 years ago

Read 2 more answers

In a redox reaction, which particles are lost and gained in equal numbers

Anna35 [415]

In a redox reaction electrons are lost and gained in equal numbers. The species that is oxidized gives electrons to the species that is reduced. I hope this helps. Let me know if anything is unclear.

5 0

4 years ago

Why are models used for understanding cells

liraira [26]

Because when you use a model you can see the cells and understand where they are located and how they work. Also a model helps you visual because you can't see cells so a model helps.

7 0

3 years ago