Question

Which of these do not obey the octet rule? select all that apply. select all that apply. clo clo− clo2− clo3− clo4−?

Answer 1

$\boxed{{\text{ClO,ClO}}_{\text{2}}^ - {\text{,ClO}}_{\text{3}}^ - {\text{,ClO}}_{\text{4}}^ - }$ does not follow the octet rule.

Further Explanation:

Octet rule: states that for the stability of any element it must have a valence shell of eight electrons (octet means a group of eight). This rule is given by Kossel and Lewis.

Atoms of same or different elements with an incomplete electronic configuration that is having electrons less than 8 are unstable and they combine together to form stable molecules with a complete octet. They can combine by sharing of electrons or loss or gain of electrons.

In ${\mathbf{ClO}}$, Chlorine (Cl) has 7 electrons in its outer shell and oxygen  has 6 electrons in its outer shell. So chlorine and oxygen share 2 electrons each to complete their octet and attain stability. Chlorine atom in the compound has ten electrons in its outer shell so it doesn’t follow the octet rule.

In ${\mathbf{Cl}}{{\mathbf{O}}^ - }$, Chlorine(Cl) has 7 electrons in its outer shell and oxygen has a unit negative charge on it $\left( {{{\text{O}}^ - }} \right)$ so, it has 7 electrons also in its outer shell. So chlorine and oxygen share one electron each to complete their octet and attain stability. All the atoms have eight electrons in their outer shell so they follow the octet rule.

In ${\mathbf{ClO}}_2^ -$, Chlorine (Cl) has 7 electrons in its outer shell and there is 2 oxygen attached to Cl. One has a unit negative charge on it $\left( {{{\text{O}}^ - }} \right)$ and the other is neutral. So, chlorine and neutral oxygen share 2 electrons each to get a stable octet and form a double bond. Similarly, chlorine shares 1 electron with oxygen ion with a negative charge on it forming a single bond with it. A chlorine atom has ten electrons in its outer shell so the compound doesn’t follow the octet rule.

In ${\mathbf{ClO}}_3^ -$, Chlorine (Cl) has 7 electrons in its outer shell and there is 3 oxygen attached to Cl. One has a unit negative charge on it $\left( {{{\text{O}}^ - }} \right)$ and the other two are neutral. So, chlorine and both neutral oxygen share 2 electrons to get a stable octet and form a double bond. Similarly, chlorine shares 1 electron with oxygen ion with a negative charge on it, forming a single bond with it. Here, Cl has ten electrons in its outer shell, so it doesn’t follow the octet rule.

In ${\mathbf{ClO}}_4^ -$ , Chlorine (Cl) has 7 electrons in its outer shell and there is 4 oxygen attached to Cl. One has a unit negative charge $\left( {{{\text{O}}^ - }} \right)$on it and the other three are neutral. So, chlorine and both neutral oxygen share 2 electrons to get a stable octet and form a double bond. Similarly, chlorine shares 1 electron with oxygen ion with a negative charge on it, forming a single bond with it.  

Here, Cl has fourteen electrons in its outer shell, so it doesn’t follow the octet rule.

Learn more:

1. The octet rule states that:brainly.com/question/1601832

2. How many covalent bond nitrogen forms: brainly.com/question/5974553

Answer details:

Grade: Secondary School

Subject: Chemistry

Chapter: Chemical Bonding

Keywords: octet rule, stability, oxygen, chlorine, covalent, sharing, ClO2-, ClO3-, ClO4-, ClO-and ClO.

Answer 2

The correct answer is ClO, ClO3-, ClO- and ClO4-

Kossel and Lewis in 1916 developed an important theory of chemical combination between atoms known as electronic theory of chemical bonding. According to this, atoms can combine either by transfer of valence electrons from one atom to another (gaining or losing) or by sharing of valence electron in order to have an octet( 8 electron) in their shells. This is known as octet rule.

In ClO2-, oxygen contains 8 electrons in its valence shell and oxygen will share one electron with chlorine to complete the octet of Cl. In other four, we can clearly see that there are more or less than 8 electrons in the outer shell of oxygen so we can clearly say that ClO, ClO3-, ClO- and ClO4-  are disobeying the octet rule.