Answer:
The heat absorbed by the sample of water is 3,294.9 J
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
The sensible heat of a body is the amount of heat received or transferred by a body when it undergoes a temperature variation (Δt) without there being a change of physical state (solid, liquid or gaseous). Its mathematical expression is:
Q = c * m * ΔT
Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case:
- Q=?
- m= 45 g
- c= 4.184
- ΔT= Tfinal - Tinitial= 38.5 C - 21 C= 17.5 C
Replacing:
Q= 4.184 * 45 g* 17.5 C
Solving:
Q=3,294.9 J
<u><em>The heat absorbed by the sample of water is 3,294.9 J</em></u>
<u><em></em></u>
<span>It is said
that the carbon atom is a tetra valence which means, it contains 4
covalent bonds that can be bonded with other atoms. Therefore, it needs 4
hydrogen atoms to bind into 1 carbon atom. Carbon Atom contains a total of
6 electrons that occupies the 2 shells which is the K (have 2 electrons)
and L (have 4 electrons) shells. The
outermost shell of carbon atoms that contains 4 electrons is called as
valence shell. In order to complete its octet, carbon Atom needs other
atoms to share their valence electrons.</span>
Answer:
6.022 × 10²³ molecules of B₂H₆
Explanation:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
B₂H₆ molecules:
21.63 g = one mole of B₂H₆= 6.022 × 10²³ molecules of B₂H₆
<span>The vaporization of br2 from liquid to gas state requires 7.4 k/cal /mol.</span>
Answer:
A mole is the amount (10) of material containing 6.02214 × 10 raised to the power of 23 particles.
