The answer is B. Decreasing the cylinder volume decreases the amount of space the gas has to occupy there for increasing pressure
The pH of the solution is 1.38.
Mass of HCl = 614 mg = 0.614 g
Moles of HCl = 0.614g / 36.5 gmol⁻¹
Concentration of HCl :
Concentration= moles/volume of solution in liters
On adding 0.01682 moles to 400 mL of water that 0.4 L of water.
[HCl]=0.01682 mol/0.4 L= 0.04205 M
HCl (s) + H₂O (l) → H₃O⁺ (aq) +Cl⁻
1 mole of HCl gives 1 mole of hydronium ion and 1 mole of chloride ions in an aqueous solution.
Then 0.04205 mol/L of HCl will give:
1x0.04205 M= 0.04205 mol/L of hydronium ions.
[H₃O⁺]= 0.04205 M
pH= -log[H₃O⁺]
pH= -log[0.04205 M]
= 1.38
The pH of the solution is 1.38.
The complete question is- A chemist dissolves 614. mg of pure hydrochloric acid in enough water to make up 400 mL of solution. Calculate the pH of the solution. Round your answer to 3 significant decimal places. X 5 ?
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B is the answer I
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A Ana
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