Determine the minimum concentration of the precipitating agent on the right to cause precipitation of the cation from the soluti
on on the left. a. 0.035 M Ba(NO3)2; NaF b. 0.085 M Calz; K2SO4 c. 0.0018 M AgNO3; RbCI
1 answer:
Answer:
a) 0.0265M
b) 8.35×10^-4M
c) 9.833×10^-8M
Explanation:
First we must write down the equation of each reaction. After identifying the insoluble precipitate, we go ahead to write down the expression for its solubility product. If the solubility product of the compound is known, the concentration of the precipitating agent can now be calculated from the available information in the question.
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Answer:
Mass of oxygen in glucose = 29.3g
Explanation:
Mass of glucose given is 55grams.
We are to find the mass of oxygen in this compound.
In the compound we have 6 atoms of oxygen.
Solution
To find the mass of oxygen in glucose, we calculate the formula mass of glucose. We now divide the formula mass of the oxygen atom with that of the glucose and multiply by the given mass to find the unkown mass.
Atomic mass of C = 12g
H = 1g
O = 16g
Formula mass of C₆H₁₂O₆ = {(12x6) + (1x12) + (16x6)} = 180
Mass of O in glucose = x 55
= x 55
= 0.53 x 55
Mass of oxygen in glucose = 29.3g