Determine the minimum concentration of the precipitating agent on the right to cause precipitation of the cation from the soluti
on on the left. a. 0.035 M Ba(NO3)2; NaF b. 0.085 M Calz; K2SO4 c. 0.0018 M AgNO3; RbCI
1 answer:
Answer:
a) 0.0265M
b) 8.35×10^-4M
c) 9.833×10^-8M
Explanation:
First we must write down the equation of each reaction. After identifying the insoluble precipitate, we go ahead to write down the expression for its solubility product. If the solubility product of the compound is known, the concentration of the precipitating agent can now be calculated from the available information in the question.
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Answer:
Explanation:
Hello,
In this case, we can consider that the given heat of combustion is indeed the heat of reaction since it corresponds to the combustion of propane, which is computed by using the heat formation of all the involved species as shown below:
Thus, since the heat of formation of gaseous carbon dioxide is -393.5 kJ/mol, water -241.8 kJ/mol and oxygen 0 kJ/mol, the heat of formation of propane is:
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The pH of the solution : 12
<h3>Further explanation</h3>Reaction
HCOOH + NaOH ⇒ HCOONa + H₂O
mol HCOOH =
mol NaOH =
Mol NaOH>mol HCOOH ⇒ at the end of the reaction there will be a strong base remains from mol NaOH, so that the pH is determined from [OH⁻]
ICE method :
HCOOH + NaOH ⇒ HCOONa + H₂O
4 5
4 4 4 4
0 1 1 1
Concentration of [OH⁻] from NaOH :
pOH=-log[OH⁻]
pOH=-log 10⁻²=2
pH+pOH=14
pH=14-2=12