Ask question

Ask question

All categories

2 years ago

10

Which of these equals 2.427? Select all that apply. A 1.34 + 1.087 B 1.4 + 1.027 C 8.35 - 5.923 - D 6 - 3.573. Please help I'm d

oing my homework

1 answer:

PtichkaEL [24]2 years ago

8 0

Answer:

All of them are equal to 2.427

Step-by-step explanation:

A = 2.427

B = 2.427

C = 2.427

D = 2.427

You might be interested in

What is her change in elevation after 5 Hours

Iteru [2.4K]

Can you add additional information about the problem?

5 0

3 years ago

Problems on a Test

patriot [66]

G = 4n is the correct equation to use. Eg 10 x 4 = 40, 18 x 4 = 72 and 21 x 4 = 84

6 0

3 years ago

Solve for x: |x − 2| + 10 = 12 (1 point)

True [87]

Answer:

I think that would be 1

Step-by-step explanation:

Do everything in the lines before anything else. -2 becomes a 2 and then you add that with the 12 and divide 12 on both sides to get one.

6 0

1 year ago

Read 2 more answers

Solve the equation. 2x squared-3x+1=0

natali 33 [55]

$2x^2-3x+1=0\\\\2x^2-2x-x+1=0\\\\2x(x-1)-1(x-1)=0\\\\(x-1)(2x-1)=0\iff x-1=0\ \vee\ 2x-1=0\ \ \ \ |+1\\\\x=1\ \vee\ 2x=1\ \ \ |:2\\\\\boxed{x=1\ \vee\ x=0.5}$

4 0

3 years ago

Which is the value of this expression when p=-2 and q=-1?

saul85 [17]

Answer:

D. 4

Step-by-step explanation:

$[(p^2) (q^{-3}) ]^{-2}.[(p)^{-3}(q)^5] ^{-2}\\\\=[(p^2) (q^{-3}) \times(p)^{-3}(q)^5 ]^{-2}\\\\=[(p^{2}) \times(p)^{-3} \times (q^{-3}) \times(q)^5 ]^{-2}\\\\=[(p^{2-3}) \times (q^{5-3}) ]^{-2}\\\\=[(p^{-1}) \times (q^{2}) ]^{-2}\\\\=(p^{-1\times (-2)}) \times (q^{2\times (-2) }) \\\\=p^{2}\times q^{-4} \\\\= \frac{p^2}{q^4}\\\\= \frac{(-2)^2}{(-1)^4}\\\\= \frac{4}{1}\\\\= 4$

8 0

2 years ago