For this case we have a function of the form 
Where:
We must find the value of the function when x = 3. Then we substitute:
Thus, the value of the function when 
is 
Answer:
Option C
Answer:
17.8333 OR 0.056074766
Step-by-step explanation:
If the fraction is 214/12, you divide the denominator by the numerator to find your decimal. 214÷12= 17.8333
If the fraction is 12/214, the decimal would be 0.056074766, or 0.06 if you round up.
This problem here would be a little tricky. Let us take into account first the variables presented which are the following: a collection of triangular and square tiles, 25 tiles, and 84 edges. Triangles and squares are 2D in shape so they give us a variable of 3 and 4 to work on those edges. Let us say that we represent square tiles with x and triangular tiles with y. There would be two equations which look like these:
x + y = 25 and 4x + 3y = 84
The first one would refer to the number of tiles and the second one to number of edges.
We will be using the first equation to the second equation and solve for one. So if we will be looking for y for instance, then x in the second equation would be substituted with x = 25 - y which would look like this:
4 (25 - y) + 3y = 84
Solve.
100 - 4y + 3y = 84
-4y +3y = 84 - 100
-y = -16
-y/-1 = -16/-1
y = 16
Then:
x = 25 -y
x = 25 - 16
x = 9
So the answer is that there are 9 square tiles and 16 triangular tiles.
Answer:
6x to find x on it's own you need to divide by the number infront,
Step-by-step explanation:
Answer:
{1, 2, 3}, {3, 4, 5}
Step-by-step explanation:
Write expressions for three consecutive integers: n, n + 1, n + 2.
Set up an equation for the verbal description: the product (mulitplication) of the two larger integers (the last two) is one less than 7 times the smallest (the first one).
(n + 1)(n + 2) = 7n - 1
Multiply (FOIL) the left side.
n^2 + 3n + 2 = 7n - 1
Subtract 7n and subtract 1 to make the right side 0.
n^2 - 4n + 3 = 0
Factor.
(n - 1)(n - 3) = 0
Set the two factors equal to 0
n - 1 = 0, n - 3 = 0
Solve for n.
n = 1, n = 3
One set of integers begins with 1, so it's {1, 2, 3}.
The other set begins with 3, so it's {3, 4, 5}
