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Thepotemich [5.8K]
2 years ago
11

Eight books, each 4.6 cm thick and of mass 1.8 kg, lie on a flat table. How much work work is required to stack them on top of o

ne another?
Physics
1 answer:
pantera1 [17]2 years ago
3 0

Answer:

529.92Newton Meters

Explanation:

Work=force x displacement

8books in total

force is 1.8kg

dispplacement is 4.6cm

times both units by 8 and u get

force - 14,4

displacement - 36.8

now times boht together and u get 529.92nm

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A ski lift is used to transport people from the base of a hill to the top. If the lift leaves the
Liono4ka [1.6K]
The energy of the ski lift at the base is kinetic energy:
K= \frac{1}{2}mv^2
where m is the mass of the ski lift+the people carried, and v=15.5 m/s is velocity at the base.
As long as the ski lift goes upward, its velocity decreases and its kinetic energy converts into potential energy. Eventually, when it reaches the top, its final velocity is v=0, so no kinetic energy is left and it has all converted into gravitational potential energy, which is 
U=mgh
where g=9.81 m/s^2 and h is the height at the top of the hill.

So, since the total energy must conserve, we have
U=K
and so
mgh =  \frac{1}{2}mv^2
from which we find the height:
h= \frac{v^2}{2g}= \frac{(15.5m/s)^2}{2\cdot 9.81 m/s^2}=12 m
8 0
3 years ago
What effect does a parachute have on the frictional force acting on the parachutist?
Schach [20]

Answer: Air resistance and/or drag.

Explanation: The parachute adds drag to the parachutist, thus making him fall slower and safely to the ground.

4 0
3 years ago
A person lowers a bucket into a well by turning the hand crank, as the drawing illustrates. The crank handle moves with a consta
dimulka [17.4K]

Answer:

0.453 m/s

Explanation:

Assuming the handle has diameter of 0.4 m while inner part diameter is 0.1 m then the circumference of outer part is \pi d_h where d is diameter and subscript h denote handle. By substituting 0.4 for the handle's diameter then cirxumference of outer part is \pi\times 0.4\approx 1.256 m

The rate of rotation will then be 1.81/1.256=1.441 rev/s

Similarly, circumference of inner part will be \pi d_i where subscript i represent inner. Substituting 0.1 for inner diameter then

\pi\times 0.1\approx 0.3142 m

The rate of rotation found for outer handle applies for inner hence speed will be 0.3142*1.441=0.453 m/s

7 0
2 years ago
A bowling ball of mass 5.8 kg moves in a straight line at 4.34 m/s How fast must a Ping-Pong ball of mass 2.214 g move in a stra
lilavasa [31]

Answer: 11369.46 m/s

Explanation:

We have the following data:

m_{1}=5.8 kg is the mass of the bowling ball

V_{1}=4.34 m/s is the velocity of the bowling ball

m_{2}=2.214 g \frac{1 kg}{1000 g}=0.002214 kg is the mass of the ping-pong ball

V_{2} is the velocity of the ping-pong ball

Now, the momentum p_{1} of the bowling ball is:

p_{1}=m_{1}V_{1} (1)

p_{1}=(5.8 kg)(4.34 m/s)  

p_{1}=25.172 kg m/s (2)

And the momentum p_{2} of the ping-pong ball is:

p_{2}=m_{2}V_{2} (3)

If the momentum of the bowling ball is equal to the momentum of the ping-pong ball:

p_{1}=p_{2} (4)

m_{1}V_{1}=m_{2}V_{2} (5)

Isolating V_{2}:

V_{2}=\frac{m_{1}V_{1}}{m_{2}} (6)

V_{2}=\frac{25.172 kg m/s}{0.002214 kg} (7)

Finally:

V_{2}=11369.46 m/s

6 0
2 years ago
A coin and feather are dropped in a moon. what will fall earlier on ground.give reasons.if they are dropped in the earth,which o
Sergeeva-Olga [200]

Answer:

  • on the moon, they will fall at the time
  • on earth, the coin will fall faster to the ground

Explanation:

A coin and feather dropped in a moon experience the same acceleration due to gravity as small as 1.625 m/s², and because of the absence of air resistance both will fall at the same rate to the ground.

If the same coin and feather are dropped in the earth, they will experience the same acceleration due to gravity of 9.81 m/s² and because of the presence of air resistance, the heavier object (coin) will be pulled faster to the ground by gravity than the lighter object (feather).

4 0
2 years ago
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