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Ivenika [448]
2 years ago
7

PLEASE HELP !!! I NEED TO PASS

Physics
1 answer:
zhannawk [14.2K]2 years ago
7 0

Answer:

Sorry I don't know the answer .Hope other help you.sorryyyyyyyy

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The lantern rises up because the __________ of the _________inside the lantern is _________ compared to the air around it
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Density, fire, less dense
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A 120.00 resistor, a 60.00 resistor, and a 40.00 resistor are connected in parallel and placed across a 12.0-V battery. What
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C

Explanation:

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2 years ago
Water flows through a cylindrical pipe of varying cross-section. The velocity is 3.0 m/s at a point where the pipe diameter is 1
Setler79 [48]

Answer:

The flow rate is  R =2.357 *10^{-4} \ m^3/s

Explanation:

From the question we are told that

    The velocity is v  =  3.0 \ m/s

   The  diameter of the pipe is  d =  1.0 \ cm  = 0.01 \ m

 

The  radius of the pipe is mathematically represented as

            r =  \frac{d}{2}

substituting values

            r =  \frac{0.01}{2}

           r =  0.005 \ m

The flow rate is mathematically represented as

       R  =  v  * A

Where is the cross-sectional area of the pipe which is mathematically evaluated as

      A   = \pi r^2

substituting values

      A   =  3.142 *  (0.005)^2

     A   = 7.855 *  10^{-5} \ m^2

So

    R  =  3.0  *  7.855 *10^{-5}

    R  =  2.357*10^{-4} \ m^3 /s

8 0
3 years ago
According to newtons second law of motion what does an object with more mass require
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the more mass something has the more force it takes to move said object.

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3 years ago
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Two charged particles are moving with equal velocities of 4.00 m/s in the +x-direction. At one instant of time the first particl
olganol [36]

Answer:

Explanation:

Electric  force between two particles

= ( 9x10⁹x7.4 x 10⁻⁶ x 3.2 x 10⁻⁶ )/  (3.2 x 10⁻²)² ( Distance between particles is 1.6 +1.6 = 3.2 cm . )

= 20.81 x 10 = 208.1 N

1 ) Magnetic field due to movement of second charge

= \frac{\mu_0}{4\pi} \frac{qv}{r^2  }

= 10⁻⁷ x 3.2 x 10⁻⁶ x 4 / (3.2 x 10⁻²)²

B = 1.25 x 10⁻⁹ T.

Due to this magnetic field , there is a force called magnetic force on first particle which will be expressed as follows

Force = Bqv

= 1.25 x 10⁻⁹ x 7.4 x 10⁻⁶ x 4

37 x 10⁻¹⁵ N

2 ) For magnetic force to be equal to electric force let velocity o particles be V

Then magnetic field due to second charge

= 10⁻⁷ x 3.2 x 10⁻⁶ x v / (3.2 x 10⁻²)²

= .3125 v x  10⁻⁹

Magnetic force on first charge

Bqv

=  .3125 v x  10⁻⁹  x 7.4 x 10⁻⁶ x v

2.3125 x 10⁻¹⁵ v²

magnetic force = electric force

2.3125 x 10⁻¹⁵ v² = 208.1

v² = 90 x 10¹⁵

v² = 900 x 10¹⁴

v = 30 x 10⁷ m /s

6 0
3 years ago
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