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Ivenika [448]
3 years ago
7

PLEASE HELP !!! I NEED TO PASS

Physics
1 answer:
zhannawk [14.2K]3 years ago
7 0

Answer:

Sorry I don't know the answer .Hope other help you.sorryyyyyyyy

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If the overall magnification of a series of two lenses is 30x, and one lens magnifies 5x, what is the magnification of the other
dimulka [17.4K]

Answer:

Explanation:

Given

Overall magnification M=30 x

One lens magnification is 5 x

suppose the magnification of other lens is y

A compound lens is made up of series of lenses either  of same or of different magnification so

y is given by

y=\frac{30 x}{5 x}=6 x

If 5 x lens is replaced by 7 x lens then total magnification is

7 x\times 6 x=42 x

4 0
3 years ago
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slava [35]
Chemical to thermal
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Help wit these questions someone.
romanna [79]

In series circuit, Req = R₁ + R₂ + R₃ + ···

In parallel circuit, \frac{1}{Req}  = \frac{1}{R1} + \frac{1}{R2} + \frac{1}{R3} +...

<h3>Q7.</h3>

total resistance in the upper branch = R₂ + R₃ = R₂ + 2

\frac{1}{Req} = \frac{1}{R2+R3} + \frac{1}{R1}

\frac{1}{4} = \frac{1}{R2+2} +\frac{1}{6}

R₂ + 2 = 12

R₂ = 10Ω

<h3>Q8.</h3>

\frac{1}{Req} = \frac{1}{R2+R3} + \frac{1}{R1}

\frac{1}{Req} = \frac{1}{2+1} + \frac{1}{4}

Req = 1.7Ω

7 0
3 years ago
What is the purpose of the scale on a map
Kryger [21]
Map scale<span> refers to the relationship (or ratio) between distance on a </span>map<span> and the corresponding distance on the ground. For example, on a 1:100000 </span>scale map<span>, 1cm on the </span>map<span> equals 1km on the ground.</span>
6 0
3 years ago
Determine the energy of light of the photon of an B4+ cation from the n = 5 energy level to n = 3? Is the energy being absorbed
Nesterboy [21]

Answer:

20.1 eV.

Explanation:

Energy of n the orbital of a hydrogen like  atom in eV having atomic no Z is given by the relation

Eₙ = -Z² x 13.6 / n² eV

For B⁴⁺ , Z = 5.

For B⁴⁺ having only one electron ( like hydrogen ) energy of n=5 orbital

E₅ = -  5² X 13.6 / 5² = - 13.6 eV.

And for n = 3

E₃ = - 5² X 13.6 / 3²

= - 37.77 eV.

Difference = 33.77-13.6  = 20.17 eV.

Light energy will be emitted when electron  transits from n = 5 to n = 3. The light will have energy equal to the difference of energy of 20.1 eV.  

3 0
3 years ago
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