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AlladinOne [14]
3 years ago
9

Ball A, moving towards the right, collides with

Physics
1 answer:
Mazyrski [523]3 years ago
8 0

Answer:

ball b has the greater mass.

Explanation:

b only moved because a bumped into it. if a bounced back, it had less mass and b moved slowly.

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Water flows in a horizontal pipe of length L. At the midpoint L/2, the pipe diameter changes. On one side of the midpoint, the p
andrew-mc [135]

Answer:

4cm

Explanation:

Hello!

To solve this problem use the following steps, the procedure is attached.

1. draw the complete outline of the problem

2. Use the continuation equation that states that the volumetric flow at the inlet of the pipe is the same as it should come out, remember that the flow is the product of the cross-sectional area by the flow rate, finally use algebra and input data to Find the exit diameter.

8 0
3 years ago
Kawas 200 osebanywhes he remembered he had to return some books they​
tia_tia [17]
I think you need to add more.. but I may know where you are leading

Was he 200 m away and made the trip in 200 seconds?

If yes...
2 m/s was his speed and 0 velocity
6 0
3 years ago
An apple is initially sitting on the bottom shelf of a pantry. A hungry physics student picks up the apple to eat it, but change
andre [41]

Answer:

Zero

Explanation:

Work done is given by multiplying force and distance moved. The distance is moved both positive and negative and it's equal distance. Since force used is the same hence work

W=F*d+ (F*-d)=0

Therefore, total work done is zero

8 0
4 years ago
A 1500 kg car is moving 18 m/s how much force is required to bring the car to a stop in 12 seconds
Marat540 [252]

Answer:

2250N

Explanation:

F = Mv/t

Force F =?

Mass M = 1500kg

Velocity v = 18m/s

Time T = 12 secs

Therefore

F = 1500 x 18 /12

Multiply through

F = 27000/12

F = 2250N

3 0
3 years ago
How high does the water rise in the bell after enough time has passed for the air to reach thermal equilibrium
Minchanka [31]

The height risen by water in the bell after enough time has passed for the air to reach thermal equilibrium is 3.8 m.

<h3>Pressure and temperature at equilibrium </h3>

The relationship between pressure and temperature can be used to determine the height risen by the water.

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where;

  • V₁ = AL
  • V₂ = A(L - y)
  • P₁ = Pa
  • P₂ = Pa + ρgh
  • T₁ = 20⁰C = 293 K
  • T₂ = 10⁰ C = 283 k

\frac{PaAL}{T_1} = \frac{(P_a + \rho gh)A(L-y)}{T_2} \\\\\frac{PaL}{T_1} = \frac{(P_a + \rho gh)(L-y)}{T_2} \\\\L-y = \frac{PaLT_2}{T_1(P_a + \rho gh)} \\\\y = L (1 - \frac{PaT_2}{T_1(P_a + \rho gh)})\\\\y = 4.2(1 - \frac{101325 \times 283}{293(101325\  +\  1000 \times  9.8 \times  100)} )\\\\y = 3.8 \ m

Thus, the height risen by water in the bell after enough time has passed for the air to reach thermal equilibrium is 3.8 m.

The complete question is below:

A diving bell is a 4.2 m -tall cylinder closed at the upper end but open at the lower end. The temperature of the air in the bell is 20 °C. The bell is lowered into the ocean until its lower end is 100 m deep. The temperature at that depth is 10°C. How high does the water rise in the bell after enough time has passed for the air to reach thermal equilibrium?

Learn more about thermal equilibrium here: brainly.com/question/9459470

#SPJ4

3 0
2 years ago
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