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AlladinOne [14]
3 years ago
9

Ball A, moving towards the right, collides with

Physics
1 answer:
Mazyrski [523]3 years ago
8 0

Answer:

ball b has the greater mass.

Explanation:

b only moved because a bumped into it. if a bounced back, it had less mass and b moved slowly.

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2000, the Millennium Bridge, a new footbridge over the River Thames in London, England, was opened to the public. However, after
sweet [91]

Answer:

n = 1810

A = 25 mm

Explanation:

Given:

Lateral force amplitude, F = 25 N

Frequency, f = 1 Hz

mass of the bridge, m = 2000 kg/m

Span, L = 144 m

Amplitude of the oscillation, A = 75 mm = 0.075 m

time, t = 6T

now,

Amplitude as a function of time is given as:

A(t)=A_oe^{\frac{-bt}{2m}}

or amplitude for unforce oscillation

\frac{A_o}{e}=A_oe^{\frac{-b(6T)}{2m}}

or

\frac{6bt}{2m}=1

or

b=\frac{m}{3T}

Now, provided in the question Amplitude of the driven oscillation

A=\frac{F_{max}}{\sqrt{(k-m\omega_d^2)+(b\omega_d^2)}}

the value of the maximum amplitude is obtained (k=m\omega_d^2)

thus,

A=\frac{F_{max}}{(b\omega_d}

Now, for n people on the bridge

Fmax = nF

thus,

max amplitude

0.075=\frac{nF}{((\frac{m}{3T})2\pi}

or

n = 1810

hence, there were 1810 people on the bridge

b)A=\frac{F_{max}}{(b\omega_d}

since the effect of damping in the millenium bridge is 3 times

thus,

b=3b

therefore,

A=\frac{F_{max}}{(3b\omega_d}

or

A=\frac{1}{(3}A_o

or

A=\frac{1}{(3}0.075

or

A = 0.025 m = 25 mm

6 0
3 years ago
An electronics technician wishes to construct a parallelplate capacitor using rutile (k=100) as the dielectric. The area of the
My name is Ann [436]

Given k=100, Area if plate A = 1.00 cm2

    = 1 x (10-2)2 m^{2}

Thickness of rutile ds = t = 1.00 mm

      = 1 x 10-3 cm

Without any dielectric medium capacitance of a parallel plate capacitor is c = oAd

When a dielectric is placed between capacitors plates then capacitance c1 = KoAd

Here d = t = 1 x 10-1 cm, o = 8.854 x 10-12 c^{2} m^{-2}  N

Now c1 = 100 X 8.859 X 10^{-12}  X 1 X (10-2)^{21}  X 10^{-2}

= 8.859 X 10-1910-3= 8.85 X 10-11 F= 8.85 X 10-12 F

 C1  = 88.5 X 10-12 F

 C1  = 88.5  PF

Correct Option: A

What purposes serve parallel plate capacitors?

The following are some uses for parallel plate capacitors:

  • This kind of capacitor is utilized in rechargeable energy systems such as batteries.
  • These capacitors are used in systems for dynamic digital memory.
  • Such capacitors are used in pulsed laser and radar circuits.

To learn more about Parallel plate capacitors, visit:

brainly.com/question/12733413

#SPJ4

5 0
2 years ago
What happens when polar molecules are between oppositely charged metal plates
KatRina [158]

Answer:

They will become aligned according to the charges on the metal plate.

Explanation:

When Polar molecules are placed between oppositely charged metal plates the molecules will tend to be attracted by their corresponding oppositely charged plates that is the positive and negative plates,

A polar molecule is one which has opposite charges on its ends. Non-polar molecules however do not have charges on their end

7 0
3 years ago
A car hits a tree with a force of 45 N, the mass of the tree is 65g. What is the resulting acceleration?
bekas [8.4K]

Answer:

i think 692m/s2 is the correct answer

4 0
3 years ago
A ball is dropped from rest at the top of a 6.10 m
natita [175]

Answer:

n = 5 approx

Explanation:

If v be the velocity before the contact with the ground and v₁ be the velocity of bouncing back

\frac{v_1}{v} = e ( coefficient of restitution ) = \frac{1}{\sqrt{10} }

and

\frac{v_1}{v} = \sqrt{\frac{h_1}{6.1} }

h₁ is height up-to which the ball bounces back after first bounce.

From the two equations we can write that

e = \sqrt{\frac{h_1}{6.1} }

e = \sqrt{\frac{h_2}{h_1} }

So on

e^n = \sqrt{\frac{h_1}{6.1} }\times \sqrt{\frac{h_2}{h_1} }\times... \sqrt{\frac{h_n}{h_{n-1} }

(\frac{1}{\sqrt{10} })^n=\frac{2.38}{6.1}= .00396

Taking log on both sides

- n / 2 = log .00396

n / 2 = 2.4

n = 5 approx

3 0
3 years ago
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