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trasher [3.6K]
4 years ago
9

Three cross-sections are extruded using an extrusion press. The first cross section is an isosceles right triangle of perpendicu

lar sides of length 0.5 inch and 1.2 inch. The second is an equilateral triangle of side 1.5 inches, the rectangle of sides 0.9 inch and 1.2 inch. Calculate the CCD for each cross-section. Determine the shape factor for each crosssection. If the original billet is of 4 inches diameter, calculate the extrusion ratio for each case.

Physics
1 answer:
olganol [36]4 years ago
7 0

Answer:

Explanation:

Find attach the shape factor and extrusion factor for the three cases.

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9) What will happen to the period of a pendulum if we change the rope of a pendulum with another which is four times with the in
Arturiano [62]

Double

Explanation:

Since the period T of a pendulum is given by

T = 2\pi \sqrt{\dfrac{l}{g}}

By increasing the length of the pendulum by 4, the period becomes

T' = 2\pi \sqrt{\dfrac{4l}{g}} = 2\left(2\pi \sqrt{\dfrac{l}{g}}\right) = 2T

You can see that the period doubles when we increase the length by a factor of 4.

5 0
3 years ago
George walks to a friend's house. He walks 850 meters north before he realizes he walked too far.
anyanavicka [17]

Answer:

<h2>44 m/s</h2>

Explanation:

In this problem we are expected to calculate the velocity of Georges movements.

Given data

Total distance covered by  George= 850+250= 1100 meters

Time taken  by  George to cover the total distance= 25 seconds

We know that velocity is, v= distance/ time

Therefore substituting our data into the expression for velocity we have

v= 1100/ 25= 44 m/s

Hence the velocity in m/s is 44

7 0
3 years ago
A stone is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stopwatch measures the stone's trajec
olga2289 [7]

Answer:

The height of the cliff is 90.60 meters.

Explanation:

It is given that,

Initial horizontal speed of the stone, u = 10 m/s

Initial vertical speed of the stone, u' = 0 (as there is no motion in vertical direction)

The time taken by the stone from the top of the cliff to the bottom to be 4.3 s, t = 4.3 s

Let h is the height of the cliff. Using the second equation of motion in vertical direction to find it. It is given by :

h=u't+\dfrac{1}{2}gt^2

h=\dfrac{1}{2}gt^2

h=\dfrac{1}{2}\times 9.8\times (4.3)^2

h = 90.60 meters

So, the height of the cliff is 90.60 meters. Hence, this is the required solution.

5 0
3 years ago
2 Points
Mademuasel [1]

According to Newton's Second Law of Motion :

The Force acting on an Object is equal to Product of Mass of the Object and Acceleration produced due to the Force.

:\implies  Force acting = Mass of the Object × Acceleration

Given : Force = 50 newton and Mass of the Object = 10 kg

Substituting the respective values in the Formula, we get :

:\implies  50 N = 10 kg × Acceleration

:\implies \mathsf{Acceleration = \dfrac{50\;N}{10\;kg}}

:\implies Acceleration of the Object = 5 m/s²

4 0
4 years ago
A police officer at rest at side of highway notices speeder moving at 62 km/h along road.when speeder passes ,officer accelerate
Korolek [52]

To answer the following questions for this specific problem:

a. 11.48 secs

b. Vp = a*t*3.6 = 3*11.48*3.6 = 124.0 km/h

<span>c. 9.1 secs. </span>

I am hoping that this answer has satisfied your query about and it will be able to help you.

4 0
3 years ago
Read 2 more answers
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