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zhenek [66]
3 years ago
6

What speed is a car going if it takes 2 hours to go 80 miles?

Physics
2 answers:
Dafna1 [17]3 years ago
8 0
Okay. If a car takes 2 hours to go 80 miles, the car is going 40 miles an hour. All you have to do is 80/2 in order to get your answer, because you do distance divided by time to find the speed.
user100 [1]3 years ago
4 0
The car would be moving at 40 miles per hour.
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In-s [12.5K]

Answer:

T = 184 seconds

Explanation:

First in order to solve this, we need to know which is the expression to calculate the period. This is an exercise of angular velocity, so:

T = 2π/w

Where w: angular speed (in rad/s)

So, let's calculate first the innitial angular speed:

w = 2π/T

Converting days to seconds:

25.4 days * 24 h/day * 3600 s/h = 2,194,560 s

Then the angular speed:

w = 2π / 2,194,560 = 2.863x10^-6 rad/s

Now, the innitial angular momentum is:

I = (2/5)Mr² replacing data:

I = 2/5* (6.96x10^8)² * M = 1.94x10^17m² * M

so the initial angular momentum would be:

L = Iω = 2.863x10^-6 * 1.94x10^17 M

L = 5.55x10^11 m²/s * M = final angular momentum

Now the  final I = 2/5Mr²

Final I = 2/5 * (6.37x10^6)² * M  = 1.62x10^13m² * M

Then 5.55x10^11m²/s * M = 1.62x10^13m² * M * ω → M cancels

ω = 3.42x10^-2 rad/s

Then the new period

T = 2π/ω = 2*3.14 / 3.42x10^-2

T = 184 seconds

8 0
3 years ago
What is the name of the force that is a combination of all forces that act on an object?
jarptica [38.1K]

Answer:

If the combination of all the forces acting on an object sums upto be zero, then the net force is known as <u>balanced force.</u>

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insens350 [35]

To solve this problem it is necessary to apply the concepts related to the Force since Newton's second law, as well as the concept of Electromagnetic Force. The relationship of the two equations will allow us to find the magnetic field through the geometric relations of density and volume.

F_{mag}= BIL

Where,

B = Magnetic Field

I = Current

L = Length

<em>Note: F_{mag}  is a direct adaptation of the vector relation F=q \times V \times B</em>

From Newton's second law we know that the relation of Strength and weight is determined as

F_g = mg

Where,

m = Mass

g = Gravitational Acceleration

For there to be balance the two forces must be equal therefore

F_{mag} = F_g

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\rho = \frac{m}{V} \rightarrow m = \rho V

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BIL = mg

BIL = ( \rho V)g

BIL = ( \rho \pi r^2 L)g

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I = \frac{( \rho \pi r^2 L)g}{BL}

I = \frac{( \rho \pi r^2 )g}{B}

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I = \frac{( (8.9*10^3 ) \pi (0.5*10^{-3})^2 )(9.8)}{5.0*10^{-5}}

I = 1370.05A

The current is too high to be transported which would make the case not feasible.

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