Question

Write the slope-intercept form of the equation that passes through the point (-1, 2) and is parallel to the line y = 3/2x + 6

Answer 1

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Answer:  $\textsf{y = 3/2x + 7/2}$

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Given: $\textsf{Passes through (-1, 2) and parallel to y = 3/2x + 6}$

Find:  $\textsf{The equation in slope-intercept form}$

Solution:  In order to determine the equation we know that our line is going to be parallel which means that the slope is the same and we need to use the point-slope form to help us.  After plugging in the values we just simplify and solve for y to convert to slope-intercept form.

Plug in the values

• $\textsf{y - y}_1\textsf{ = m(x - x}_1\textsf{)}$

• $\textsf{y - 2 = 3/2(x - (-1))}$

Simplify and distribute

• $\textsf{y - 2 = 3/2(x + 1)}$

• $\textsf{y - 2 = (3/2 * x) + (3/2 * 1)}$

• $\textsf{y - 2 = 3/2x + 3/2}$

Add 2 to both sides

• $\textsf{y - 2 + 2 = 3/2x + 3/2 + 2}$

• $\textsf{y = 3/2x + 3/2 + 2}$

• $\textsf{y = 3/2x + 7/2}$

Therefore, after completing the steps we were able to determine that the equation that fits the description is y = 3/2x + 7/2.