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allochka39001 [22]
2 years ago
6

What is a vocab word for newton's second law?

Chemistry
2 answers:
olga nikolaevna [1]2 years ago
8 0

Answer:

proportional. having a constant ratio. Second law: A body of mass m subject to a net force F undergoes an acceleration a that has the same direction as the force and a magnitude that is directly proportional to the force and inversely proportional to the mass, i.e., unbalanced.

Explanation:

hope it's help

Julli [10]2 years ago
7 0
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
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A solid piece of lead has a mass of 23.94g and a volume of 2.10cm^3. from these data, calculate the density of lead in si units
jeyben [28]
A density of a substance is constant. It is an extensive property, meaning it does not depend on the amount of substance because it is a ratio of mass to volume. No matter how much of each there is, they would always have a fixed ratio called density. For lead, the density is

Density = mass/volume
Density = 23.94 g/ 2.10 cm³
Density = 11.4 g/cm³
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3 years ago
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Increasing the temperature increases the vaporization rate of a liquid because the excess energy is used to break covalent bonds
igor_vitrenko [27]

Answer:

False

Explanation:

False.  The molecules of liquid are hold in the liquid state due to intermolecular forces or Van de Waals forces , without affecting the molecule itself and its atomic bonds (covalent bonds).  When the temperature increases the kinetic energy of the molecules is higher , therefore they have more possibilities to escape from the attractive intermolecular forces and go to the gas state.

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4 0
3 years ago
How many moles of copper are there in 6.93 g of copper sample<br>pls be quick​
Alex_Xolod [135]
  • Molar mass of copper=63.5g/mol
  • Given mass=6.93g

\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}

\\ \sf\longmapsto No\:of\:moles=\dfrac{6.93}{63.5}

\\ \sf\longmapsto No\:of\:moles=0.109\approx 1.11moles

7 0
2 years ago
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olga55 [171]

Answer:

222325332

Explanation:

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