Answer:
There is 257 mL of a 0.175 M FeCl3 solution needed.
Explanation:
Step 1: Data given
Fecl3 → Fe3+ + 3Cl-
This means that for 1 mole Fecl3 consumed, there is produced 1 mole of Fe3+ and 3 moles of Cl-
The FeCl3 solution has a molarity of 0.175 M
The molarity of the Cl- ion is 0.300 M
The solution has a volume of 450 ml = 0.450 L
Step 2: Calculate the volume
M1V1 = M2V2
with M1 = 0.175*3 = 0.525 M
with V1 = TO BE DETERMINED
with M2 = 0.300 M
with V2 = 450 mL = 0.450 L
0.525 M * V1 = 0.300 M * 0.450 L
V1 = 0.135 / 0.525 M = 0.257 L = 257 mL
There is 257 mL of a 0.175 M FeCl3 solution needed.
