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PSYCHO15rus [73]
2 years ago
12

PLEASE HELP NO ONE HAS BEEN ANSWERING AT ALL!!!! I WILL GIVE BRAINLIEST! With a headwind a plane traveled 128 km in 2h. The retu

rn trip with a tail wind took 24 min less. Find the air speed of the plane. A. 64 km/h B. 72km/h C. 80km/h D. 88km/h E. 96km/h
Mathematics
1 answer:
djverab [1.8K]2 years ago
4 0

Answer:

Step-by-step explanation:

B

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The diameter of a circle is 16 kilometers. Find the area of the circle.
Elden [556K]

The diameter of a circle is 16 kilometers. Then the area of the circle is 201.062 \mathrm{km}^{2}

<u>Solution:</u>

Given that , the diameter of a circle is 16 kilometers  

We have to find the area of the circle .

Radius is half of diameter.

\begin{array}{l}{\text { diameter }=2 \times \text { radius } \rightarrow \text { radius }=\frac{\text {diameter}}{2}} \\\\ {\rightarrow \text { radius }=\frac{16}{2} \rightarrow \text { radius }=8 \text { kilometers. }}\end{array}

<em><u>The area of circle is given as:</u></em>

\begin{array}{l}{\text { area of a circle }=\pi \times r^2 \\ {\text { Area of a circle }=\pi \times 8^{2}=\pi \times 64=64 \times 3.14=201.062}\end{array}

Hence, the area of the circle is 201.062 km^2

4 0
3 years ago
A seventh-grade student forgets to bring his lunch money on several occasions. Each time he forgets his lunch money, he has to c
Georgia [21]

Answer:

-12.6

Step-by-step explanation:

6 0
3 years ago
Drag steps in the given order to evaluate this expression. <br><br> (4)(−3)−5−3(−6)
never [62]

Answer:

1

Step-by-step explanation:

using PEDMAS(parentheses, exponents, division, multiply, addition, subtraction) to solve the problem

First we multiply (4)(-3)

(4)(−3)−5−3(−6)

Then multiply -3(-6)

(-12)-5-3(-6)

=-12-5+18

subtract 12-5

-12-5+18

=-17+18

Adding -17+18 gives us 1.

Therefore,  (4)(−3)−5−3(−6) is 1.

3 0
4 years ago
in the circl below, AD is diameter and AB is tangent at A. Suppose mADC=228*, find the measures of mCAB and mCAD. Type your nume
Andrew [12]

Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

To find:

The m\angle CAB and m\angle CAD.

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

m(arcADC)=m(arcAD)+m(arcDC)

228^\circ=180^\circ+m(arcDC)

228^\circ-180^\circ+=m(arcDC)

48^\circ+=m(arcDC)

The measure inscribed angle is half of the corresponding subtended arc.

m\angle CAD=\dfrac{1}{2}\times m(arcDC)

m\angle CAD=\dfrac{1}{2}\times 48^\circ

m\angle CAD=24^\circ

AB is the tangent. So, m\angle BAD=90^\circ because radius is perpendicular on the tangent and the point of tangency.

m\angle BAD=m\angle CAB+m\angle CAD

90^\circ=m\angle CAB+24^\circ

90^\circ -24^\circ=m\angle CAB

66^\circ=m\angle CAB

Therefore, m\angle CAB=66^\circ and m\angle CAD=24^\circ.

4 0
3 years ago
Suppose that an airline overbooks seats on their flights. In particular, it sells 300 tickets for a flight when there are only 2
vladimir1956 [14]

Using the <u>normal approximation to the binomial</u>, it is found that there is a 0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • The binomial distribution is the probability of <u>x successes on n trials</u>, with <u>p probability</u> of a success on each trial. It can be approximated to the normal distribution with \mu = np, \sigma = \sqrt{np(1-p)}.

In this problem:

  • 15% do not show up, so 100 - 15 = 85% show up, which means that p = 0.85.
  • 300 tickets are sold, hence n = 300.

The mean and the standard deviation are given by:

\mu = np = 300(0.85) = 255

\sigma = \sqrt{np(1-p)} = \sqrt{300(0.85)(0.15)} = 6.185

The probability that we will have enough seats for everyone who shows up is the probability of at most <u>270 people showing up</u>, which, using continuity correction, is P(X \leq 270 + 0.5) = P(X \leq 270.5), which is the <u>p-value of Z when X = 270.5</u>.

Z = \frac{X - \mu}{\sigma}

Z = \frac{270.5 - 255}{6.185}

Z = 2.51

Z = 2.51 has a p-value of 0.994.

0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

A similar problem is given at brainly.com/question/24261244

8 0
3 years ago
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