The diameter of a circle is 16 kilometers. Then the area of the circle is 
<u>Solution:</u>
Given that , the diameter of a circle is 16 kilometers
We have to find the area of the circle .
Radius is half of diameter.

<em><u>The area of circle is given as:</u></em>

Hence, the area of the circle is 201.062 
Answer:
1
Step-by-step explanation:
using PEDMAS(parentheses, exponents, division, multiply, addition, subtraction) to solve the problem
First we multiply (4)(-3)
(4)(−3)−5−3(−6)
Then multiply -3(-6)
(-12)-5-3(-6)
=-12-5+18
subtract 12-5
-12-5+18
=-17+18
Adding -17+18 gives us 1.
Therefore, (4)(−3)−5−3(−6) is 1.
Given:
AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.
To find:
The
and
.
Solution:
AD is diameter of the circle. So, the measure of arc AD is 180 degrees.




The measure inscribed angle is half of the corresponding subtended arc.



AB is the tangent. So,
because radius is perpendicular on the tangent and the point of tangency.




Therefore,
and
.
Using the <u>normal approximation to the binomial</u>, it is found that there is a 0.994 = 99.4% probability that we will have enough seats for everyone who shows up.
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- The binomial distribution is the probability of <u>x successes on n trials</u>, with <u>p probability</u> of a success on each trial. It can be approximated to the normal distribution with
.
In this problem:
- 15% do not show up, so 100 - 15 = 85% show up, which means that
. - 300 tickets are sold, hence
.
The mean and the standard deviation are given by:


The probability that we will have enough seats for everyone who shows up is the probability of at most <u>270 people showing up</u>, which, using continuity correction, is
, which is the <u>p-value of Z when X = 270.5</u>.



has a p-value of 0.994.
0.994 = 99.4% probability that we will have enough seats for everyone who shows up.
A similar problem is given at brainly.com/question/24261244