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kenny6666 [7]
3 years ago
13

How do I solve 5(3m-6)

Mathematics
1 answer:
son4ous [18]3 years ago
6 0

Answer: follow my steps below

Step-by-step explanation:

First, remove the variable so as to not confuse you.

You always multiply whats on the outside to what inside parentheses. 5×3 is 15 and 5×6 is 30

Next, you subtract to get the negative. -15

So for you final answer, it's -15m

Hope this helps

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Divide. Express each answer as a decimal.
dem82 [27]
1: 2.5 2:0.4 3:12.5 4:0.08 hope this helps
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Can you help me on this? Thanks​
Citrus2011 [14]

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8 0
2 years ago
Bilal’s favorite colors are red and green
Rus_ich [418]
Answer: P(A∪B) = 1/3

Step-by-step explanation:
Red Garments = 1 red shirt + 1 red hat + 1 red pairs of pants
Total Red Garments = 3
Green Garments = 1 green shirt + 1 green scarf + 1 green pairs of pants
Total Green Garments = 3
The total number of garments = Total Red Garments + Total Green Garments:
3 + 3 = 6
Let A be the event that he selects a green garment
P(A) = Number of required outcomes/Total number of possible outcomes
P(A) = 3/6
Let B be the event that he chooses a scarf
P(B) = 1/6
The objective here is to determine P(A or B) = P(A∪B)
Using the probability set notation theory:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∩B) = Probability that a green pair of pant is chosen = P(A) - P(B)
= 3/6-1/6
= 2/6
P(A∪B) = 1/2 + 1/6 - 2/6
P(A∪B) = 2/6
P(A∪B) = 1/3

I hope this helps. :)
7 0
2 years ago
Perform the indicated operation. Simplify the result in factored form.
vfiekz [6]

Answer:

\frac{a+1}{(a-2)(a-1)(a-1)}=

Step-by-step explanation:

1. Approach

The easiest method to solve this problem is to factor the expression. In order to subtract (or add) two fractions, both fractions have to have common denominators. When the fractions are factored one can easily see the least common denominator. Convert both fractions to the least common denominator by multiplying the numerator (number over the fraction bar) and denominator (number under the fraction bar) by the value such that both fractions have the same denominator. Finally, one can subtract the numerators of the two fractions.

2. Factoring and Least common denominator

\frac{3}{a^2-3a+2}-\frac{2}{a^2-1}=

Factor the expression, rewrite the quadratic polynomials as the product of two linear polynomials,

\frac{3}{a^2-3a+2}-\frac{2}{a^2-1}=

\frac{3}{(a-2)(a-1)}-\frac{2}{(a-1)(a+1)}=

The least common denominator is: ((a-2)(a-1)(a-1))

Convert both fractions to the least common denominator, multiply both the numerator and denominator by the same value to do so,

\frac{3}{(a-2)(a-1)}-\frac{2}{(a-1)(a+1)}=

\frac{3}{(a-2)(a-1)}*\frac{a-1}{a-1}-\frac{2}{(a-1)(a+1)}*\frac{a-2}{a-2}=

Simplify,

\frac{3}{(a-2)(a-1)}*\frac{a-1}{a-1}-\frac{2}{(a-1)(a+1)}*\frac{a-2}{a-2}=

\frac{3(a-1)}{(a-2)(a-1)(a-1)}-\frac{2(a-2)}{(a-1)(a+1)(a-2)}=

3. Solving the expression

\frac{3(a-1)}{(a-2)(a-1)(a-1)}-\frac{2(a-2)}{(a-1)(a+1)(a-2)}=

Distribute, multiply every term inside the parenthesis by the term outside of it,

\frac{3(a-1)}{(a-2)(a-1)(a-1)}-\frac{2(a-2)}{(a-1)(a+1)(a-2)}=

\frac{3a-3}{(a-2)(a-1)(a-1)}-\frac{2a-4}{(a-1)(a+1)(a-2)}=

Simplify further,

\frac{3a-3}{(a-2)(a-1)(a-1)}-\frac{2a-4}{(a-1)(a+1)(a-2)}=

\frac{3a-3-(2a-4)}{(a-2)(a-1)(a-1)}=

\frac{3a-3-2a+4}{(a-2)(a-1)(a-1)}=

Combine like terms,

\frac{3a-3-2a+4}{(a-2)(a-1)(a-1)}=

\frac{a+1}{(a-2)(a-1)(a-1)}=

4 0
2 years ago
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