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4vir4ik [10]
3 years ago
8

The area of a garden is 12.9 square feet. each square foot of the garden needs to have 2.6 pounds of soil. how many pounds of so

il are needed for the garden? enter your answer in the box.
Mathematics
2 answers:
ikadub [295]3 years ago
4 0
4.9 is the right answer hope i helped
Leno4ka [110]3 years ago
3 0

Answer:

33.54

Step-by-step explanation:

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Line 1 passes through the points (-4, -6) and (12,2). line 2 passes through the points (-6,-2) and (-2,0). Do the lines intersec
kifflom [539]

The lines dont intersect

7 0
3 years ago
A model car uses the scale 1:43. The actual length of a car is 17.2 feet. What is the length of the model car?
faust18 [17]
17.2/43= 0.4

Since the scale is 1:43, you would just divide the actual length by 43.

0.4:17.2 is congruent to 1:43.

43/17.2= 2.5

1/.04= 2.5

I hope this helps!
~kaikers
7 0
3 years ago
A 100 foot ladder is leaning against a tree so that the top of the ladder is 96 feet above the ground. How far is the base of th
ahrayia [7]

Answer:The base of the ladder from the tree is 28ft

Step-by-step explanation:

Using pythagorean theorem

Let 100ft= hypothesis is the right angle triangle

Let 96ft be the height of the ladder

Let x be the base of the right angle triangle between the base of the ladder and the tree

h^2=a^2+b^2

100^2=96^2 +b^2

10,000=9216 +b^2

b^2=10,000-9216

b=sqrt(784)

b=28ft

8 0
3 years ago
Read 2 more answers
What is the answer I need help? <br>PLZ HELP ME
Firlakuza [10]
Use an app called Socratic, take a photo of the questions you're stuck on, then it will help you in stages and show you the answer.

This app gives you *instant* homework answers, all subjects Get it: https://socratic.org/a/p04dj0084n

6 0
3 years ago
Ax +by=c solve for y
hichkok12 [17]

Answer:

y = c/b - (A x)/b

Step-by-step explanation:

Solve for y:

A x + b y = c

Hint: | Isolate terms with y to the left hand side.

Subtract A x from both sides:

b y = c - A x

Hint: | Solve for y.

Divide both sides by b:

Answer:  y = c/b - (A x)/b

6 0
2 years ago
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