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Lisa [10]
2 years ago
11

BRAINLIEST PLEASE: You throw a small rock straight up from the edge of a highway bridge that crosses a river. The rock passes yo

u on its way down, 8.00 s after it was thrown. What is the speed of the rock just before it reaches the water 29.0 m below the point where the rock left your hand? Ignore air resistance.
Physics
1 answer:
Sophie [7]2 years ago
3 0

Answer:

The velocity with which the stone strikes the water surface is 33.0 m/s (nearest tenth)

Explanation:

Good luck!

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A treasure map instructs you to walk (25.0+A) m south, followed by (18.0+B) m east, then 64.5 m north, and finally 28.5 m east.
adelina 88 [10]

Answer:

Explanation:

Check attachment for solutions

3 0
3 years ago
What is the answer?​
scoundrel [369]

"Choice-C" is the answer.

7 0
3 years ago
As a rocket rises, its kinetic energy changes. At the time the rocket reaches its highest point, most of the kinetic energy of r
Ulleksa [173]
<span>D transformed into gravitational potential energy.</span>
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3 years ago
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At some airports there are speed ramps to help passengers get from one place to another. A speed ramp is a moving conveyor belt
Amanda [17]

Answer:

The time taken is t_s = 31.16 s

Explanation:

From the question we are told that

   The length of the speed ramp is L = 104m

     The speed of the speed ramp is v_r  = 2.1 m/s

      The time taken to cover the distance is t = 84 s

     

The walking speed( when not on the speed ramp)  required to  cover the 104m is mathematically represented as

                     v_w = \frac{L}{t}

Substituting values

                      v_w = \frac{104}{84}

                            = 1.238 m/s

The speed required to cover the 104m distance when on a speed speed ramp  is mathematically represented as

     v = The\ walking\ speed  +  speed \ of \ the \ speed \ ramp

 substituting values

               v = 2.1 + 1.238

               v = 3.338 m/s

Now the time taken to travel the 104m distance when walking on the speed ramp is mathematically evaluated as

                t_s = \frac{L}{v}

                     = \frac{104}{3.338}

                     t_s = 31.16 s

             

4 0
3 years ago
Read 2 more answers
A remote-controlled boat traveled 18 feet heading west and 24 feet heading south, totaling 42 feet over the course of 10 seconds
Dominik [7]

Answer:

3 ft/s

Explanation:

given,

distance in west, d₁ = 18 ft

distance in south, d₂ = 24 ft

time taken to travel 42 ft = 10 s

speed of boat in north = x ft/s

Speed of the boat when heading west = (x - 3) ft/s

Average\ speed = \dfrac{total\ distance}{total\ time}

v_{avg}= \dfrac{42}{10}

v_{avg}= 4.2\ ft/s

again using the above formula

now, total time

t = t₁ + t₂

10 = \dfrac{18}{x-3} + \dfrac{24}{x}

on simplifying

10 x² -72 x + 72 = 0

On solving the above equation we get

x = 6 ft/s

Hence, speed of boat in west direction, 6 -3 = 3 ft/s

           speed of boat in south direction = 6 ft/s

3 0
3 years ago
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