Answer:
The work done is 10.64Joules
Answer:
<em>6.77m/s</em>
Explanation:
Using the law of conservation of momentum
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses of the object
u1 and u2 are the velocities before collision
v is the final collision
Given
m1 = 300g = 0.3kg
u1 = 6.0m/s
m2 = 10g = 0.01kg
u2 = 30m/s
Required
The bird's speed immediately after swallowing v
Substitute the given values into the formula
m1u1 + m2u2 = (m1+m2)v
0.3(6) + 0.01(30) = (0.3+0.01)v
1.8+0.3 = 0.31v
2.1 = 0.31v
v = 2.1/0.31
<em>v = 6.77m/s</em>
<em>Hence the bird's speed immediately after swallowing is 6.77m/s</em>
Answer:
Recoil speed, 
Explanation:
Given that,
Mass of the comet fragment, 
Speed of the comet fragment, 
Mass of Callisto, 
The collision is completely inelastic. Assuming for this calculation that Callisto's initial momentum is zero. So,
V is recoil speed of Callisto immediately after the collision.
So, the recoil speed of Callisto immediately after the collision is
Answer:
A. Equal to and Opposite
Explanation:
when there is no External force acting on the system of bodies then Net momentum of the system is Conserved .
Given that there are 2 bodies
Let P₁ as first object's momentum
P₂ as second object's momentum.
Total Momentum =P₁ + P₂
As there is no external force acying on the system
Change in the Total momentum is zero
so,
0 = Δ P₁ + ΔP₂
ΔP₂ = -ΔP₁
negative sign indicates opposite direction.
Both are of equal magnitude.
