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kati45 [8]
3 years ago
9

a doghouse has a mass of 98 kg, and the coefficient of friction between it and the ground is 0.95. what is the maximum force of

friction between the doghouse and the ground?
Physics
2 answers:
lapo4ka [179]3 years ago
4 0

Answer:

Maximum force of friction, F = 912.38 N

Explanation:

It is given that,

Mass of doghouse, m = 98 kg

Coefficient of friction between doghouse and the ground, μ = 0.95

We have to find the maximum force of friction between the doghouse and the ground. It is given by :

F = μ N

N = normal force = mg

F = μmg

F = 0.95 × 98 kg × 9.8 m/s²

F = 912.38 N

Hence, this is the required solution.

MaRussiya [10]3 years ago
3 0
The maximum force of friction:

F = μ* N, where μ is the friction coefficient and N id the force of the doghouse normal to the surface.

N for a flat surface would be: N = m*g, where m is the mass and g is the gravitational acceleration = 9,81 m/s².

Combined:

F = μ * g * m
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3 years ago
A small apple weighs 0.8N. How much would an apple that is 4 times as massive weigh?
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A stretched string has a mass per unit length of 5.40 g/cm and a tension of 17.5 N. A sinusoidal wave on this string has an ampl
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Answer:

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part b)

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Part d)

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Explanation:

As we know that the speed of wave in string is given by

v = \sqrt{\frac{T}{m/L}}

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v = \sqrt{\frac{17.5}{0.54}}

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Part a)

y_m = amplitude of wave

y_m = 0.157 mm

part b)

k = \frac{\omega}{v}

here we know that

\omega = 2\pi f

\omega = 2\pi(92.2) = 579.3 rad/s

so we  have

k = \frac{579.3}{5.69}

k = 101.8 rad/m

Part c)

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Part d)

here since wave is moving in negative direction so the sign of \omega must be positive

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