Easy ones! giving brainly if correct. answering both questions would be nice

A container of gas has a volume of 280 mL at a temperature of 22 Celsius if the pressure remains constant what is the volume 44

d1i1m1o1n [39]

Answer:

300.9mL

Explanation:

Given parameters:

V₁ = 280mL

T₁ = 22°C

T₂ = 44°C

Unknown:

V₂ = ?

Solution:

To solve this problem, we apply Charles's law;

it is mathematically expressed as;

$\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

We need to convert the temperature to kelvin;

T₁ = 22°C = 22 + 273 = 295K

T₂ = 44°C = 44 + 273 = 317K

Input the parameters and solve;

$\frac{280}{295}$ = $\frac{V_{2} }{317}$

V₂ x 295 = 280 x 317

V₂ = 300.9mL

5 0

3 years ago

Please help its difficult

Likurg_2 [28]

Answer:

$pounds$

pounds pounds pounds

8 0

2 years ago

If the relative activities of two metals are known which metal is more easily oxidized

Ksivusya [100]

Answer: The metal that has a greater reactivity is more easily oxidized.

Explanation:

Oxidation is when the elements lose electrons and increase their oxidation state.

The metals tend to react by losing electrons and form the corresponding cation.

For expample, sodium (an alkalyne metal) loses one elecron and form the cation Na¹⁺ , then this cation combine with an anion and form compounds like NaCl, NaOH. The same do the other alkalyne metals.

Magnesium (an alkalyne earth metal) loses two electrons and form the cation Mg²⁺, then it combines with some anions to form compounds, like MgSO₄, Mg(OH)₂.

So, the easier the metal gets oxidized the greater its reactivity.

6 0

3 years ago

When the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is

gizmo_the_mogwai [7]

Answer : The correct option is, (D) 100 times the original content.

Explanation :

As we are given the pH of the solution change. Now we have to calculate the ratio of the hydronium ion concentration at pH = 5 and pH = 3

As we know that,

$pH=-\log [H_3O^+]$

The hydronium ion concentration at pH = 5.

$5=-\log [H_3O^+]$

$[H_3O^+]=1\times 10^{-5}M$ ..............(1)

The hydronium ion concentration at pH = 3.

$3=-\log [H_3O^+]$

$[H_3O^+]=1\times 10^{-3}M$ ................(2)

By dividing the equation 1 and 2 we get the ratio of the hydronium ion concentration.

$\frac{[H_3O^+]_{original}}{[H_3O^+]_{final}}=\frac{1\times 10^{-5}}{1\times 10^{-3}}=\frac{1}{100}$

$100\times [H_3O^+]_{original}=[H_3O^+]_{final}$

From this we conclude that when the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is 100 times the original content.

Hence, the correct option is, (D) 100 times the original content.

7 0

3 years ago

Read 2 more answers

Which of the following acids is the WEAKEST? The acid is followed by its Ka value.HF, 3.5 × 10^-4HNO2, 4.6 × 10^-4HCN, 4.9 × 10^

Mila [183]

Answer:

HCN

Explanation:

There are several factors that can tell us when an acid is stronger than another, which are the following:

1. The Polarity of the X - H Bond

2. Size of the X atom.

3. Charge on the acid.

4. Oxidation state of the central atom

5. Values of Ka and pKa.

From all of this factors, we can see that the exercise is already giving us values of Ka, and also we have different types of acid, not only with the form H - X

So, we will base the force of an acid by it's pKa value.

The pKa value which is calculated with the expression:

pKa = -logKa

pKa is a value that indicates how strong is the acid you are working with. This value can vary depending on factors such the charge of the acid. I f this charge can be easily distributed in resonance structures, the compound is more acidic, and therefore the pKa value is lower.

The lower the pKa, the more acidic the compound is.

So calculating the pKa on every structure we have:

HF: pKa = -log(3.5x10^-4) = 3.46

HNO2: pKa = -log(4.6x10^-4) = 3.34

HCN: pKa = -log(4.9x10^-10) = 9.31

HCOOH: pKa = -log(1.8x10^-4) = 3.74

HClO2: -log(1.1x10^-2) = 1.96

So according to all this values, we can conclude that the weakest acid is the HCN

4 0

3 years ago

Easy ones! giving brainly if correct. answering both questions would be nice​

Easy ones! giving brainly if correct. answering both questions would be nice