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zavuch27 [327]
2 years ago
5

How do you break down an element?

Chemistry
1 answer:
makkiz [27]2 years ago
5 0

Answer:

<h3><em><u>elements</u></em><em><u> </u></em><em><u>cannot</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>break</u></em><em><u> </u></em><em><u>down</u></em><em><u> </u></em></h3>
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What volume will be occupied by .756 mole of gas at 109 kPa and 30.5 degrees C
olga2289 [7]

Answer: it would be 0.026 moles

Explanation: PV=nRT, P is the pressure of gas, V is the volume it occupies n is the number of moles of gas present in the sample, R is the universal gas constant which is equal to 0.0821 atm L/mol K and T is the absolute temperature of the gas

8 0
3 years ago
In order to prepare 50.0 mL of 0.100 M NaOH you will add _____ mL of 1.00 M NaOH to _____ mL of water
FinnZ [79.3K]

The question requires us to complete the sentence regarding the preparation of a more dilute NaOH solution (0.100 M, 50.0 mL) from a more concentrated NaOH solution (1.00 M).

Analyzing the blank spaces that we need to fill in the sentence, we can see that we must provide the volume of the more concentrated solution and the volume of water necessary to prepare the solution.

We can use the following equation to calculate the volume of more concentrated solution required:

\begin{gathered} C_1\times V_1=C_2\times V_2 \\ V_1=\frac{C_2\times V_2}{C_1} \end{gathered}

where C1 is the concentration of the initial solution (C1 = 1.00 M), V1 is the volume required of the inital solution (that we'll calculate), C2 is the concentration of the final solution (C2 = 0.100 M) and V2 is the volume of the final solution (V2 = 50.0 mL).

Applying the values given by the question to the equation above, we'll have:

\begin{gathered} V_1=\frac{C_2\times V_2}{C_1} \\ V_1=\frac{0.100M_{}\times50.0mL_{}}{1.00M_{}}=5.00mL \end{gathered}

Thus, we would need 5.00 mL of the more concentrated solution.

Since the volume of the final solution is 50.0 mL and it corresponds to the volume of initial solution + volume of water, we can calculate the volume of water necessary as:

\begin{gathered} \text{final volume = volume of initial solution + volume of water} \\ 50.0mL=5.00mL\text{ + volume of water} \\ \text{volume of water = 45.0 mL} \end{gathered}

Thus, we would need 45.0 mL of water to prepare the solution.

Therefore, we can complete the sentence given as:

<em>"In order to prepare 50.0 mL of 0.100 M NaOH you will add </em>5.00 mL<em> of 1.00 M NaOH to </em>45.0 mL<em> of water"</em>

5 0
1 year ago
What mass of calcium chloride is produced from 5.59 mol of hydrochloric acid
svp [43]

From the mole ratio of the reaction as given in the equation of the reaction, the mass of calcium chloride that can be produced from 5.59 mol of hydrochloric acid is 310.245 g.

<h3>What mass of calcium chloride can be produced from 5.59 mol of hydrochloric acid?</h3>

The mass of calcium chloride that can be produced from 5.59 mol of hydrochloric acid is determined from the equation of the reaction.

The equation of the reaction is given below:

Ca²⁺ (aq) + 2 HCl (aq) ---> CaCl₂ (s) + H₂ (g)

From the equation of the reaction, the mole ratio of HCL and calcium chloride is 2 : 1

Therefore, moles of calcium chloride that can be produced will be:

The moles of calcium chloride = 5.59 moles * 1/2

The moles of calcium chloride = 2.795 moles

The mass of calcium chloride produced = moles * molar mass

Molar mass of calcium chloride = 111 g/mol

Mass of calcium chloride produced = 2.795 * 111

Mass of calcium chloride produced = 310.245 g

Learn more about mole ratio at: brainly.com/question/19099163

#SPJ1

6 0
1 year ago
In the periodic table, group 15 all have _____ valence electrons. 2 4 5 6
maxonik [38]
5 valence electrons

filler text filler text filler text
8 0
3 years ago
Read 2 more answers
If a student calculated 0.03256 moles of copper metal (Cu0), how many grams of copper metal (Cu0) should be recovered at the end
Liula [17]

Answer:

Mass of copper metal will be 2.06756 gram

Explanation:

We have given number of moles of copper n = 0.03256

Molar mass of copper = 63.5 u

We have to calculate mass of copper metals in gram

We know that number of moles is given by number\ of\ moles=\frac{mass\ in\ gram}{molar\ mass}

0.03256=\frac{mass\ in\ gram}{63.5}

Mass in gram = 2.06756 gram

So mass of copper metal will be 2.06756 gram

7 0
3 years ago
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