Answer:
Moles of NO₂ = 0.158
Explanation:
SO 2 ( g ) + NO 2 ( g ) ⇄ SO 3 ( g ) + NO ( g )
According to the law of mass equation
= ![\frac{[SO_{3} ][NO]}{[SO_{2}][NO_{2} ]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BSO_%7B3%7D%20%5D%5BNO%5D%7D%7B%5BSO_%7B2%7D%5D%5BNO_%7B2%7D%20%20%5D%7D)
⇒ 3.10 = ![\frac{(1.00)(1.00)}{(2.30) [NO_{2} ]}](https://tex.z-dn.net/?f=%5Cfrac%7B%281.00%29%281.00%29%7D%7B%282.30%29%20%5BNO_%7B2%7D%20%5D%7D)
At equilibrium [SO₃] = [NO]
⇒ [NO₂] = 
⇒ [NO₂] = 0.158
So. number of moles of NO₂ at equilibrium added = 0.158
Answer:
what is this i dont know what kind of math this is
The balanced equation for the reaction is as follows;
Li₂O + H₂O ---> 2LiOH
Stoichiometry of Li₂O to H₂O is 1:1
Mass of Li₂O reacted - 18.9 g
Number of Li₂O moles reacted - 18.9 g / 30 g/mol = 0.63 mol
An equivalent amount of moles of water have reacted - 0.63 mol
mass of water required - 0.63 mol x 18 g/mol = 11.34 g
A mass of 11.34 g of water is required
I didn't know if you meant to the power of 14 but if you did here your answer:
3.64 x 10^-19
(you just multiply the frequency by Planck's constant= 6.63 × 10^–34)
Answer:
B. The effects of warmed water on aquatic life
Explanation:
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