All categories

3 years ago

Predict the missing particle or nuclide.

Chemistry

1 answer:

Advocard [28]3 years ago

8 0

Answer:

beta minus emission

Explanation:

Beta radiations:

Beta radiations are result from the beta decay in which electron is ejected. The neutron inside of the nucleus converted into the proton an thus emit the electron which is called β particle.

The mass of beta particle is smaller than the alpha particles.

They can travel in air in few meter distance.

These radiations can penetrate into the human skin.

The sheet of aluminum is used to block the beta radiation

²³⁹₉₃Np→ ²³⁹₉₄Pu + ⁰₋₁e

The beta radiations are emitted in this reaction. The one electron is ejected and neutron is converted into proton.

You might be interested in

What is the average atomic mass of einsteinium? what are its common isotopes?

uysha [10]

Answer:

Boom

Explanation:

The bomb is big and it goes boom and it also creates nuclear fragments everywhere

3 0

3 years ago

If a radioisotope has a half-life of 4 years, how much remains of a starting amount of 40 grams after 16 years have passed?

Gwar [14]

Answer:

only 2.5 grams will be present after 16 years have passed

5 0

3 years ago

Write an investigative question

pshichka [43]

Answer:

What happened?

What was the date, time and duration of the incident or behavior?

How many times did this happen?

Where did it happen?

How did it happen?

Did anyone else see it happen? Who? What did they say? What did they do?

Was there physical contact? Describe it. Demonstrate it.

What did you do in response to the incident or behavior?

What did you say in response to the incident or behavior?

How did the subject of the allegation react to your response?

Did you report this to anyone in management? To whom? When? What they say and/or do?

Did you tell anyone about the incident or behavior? Who? What did they say and/or do?

Do you know whether the subject of the allegation has been involved in any other incidents?

Do you know why the incident or behavior occurred?

Do you know anyone else who can shed light on this incident?

Is there anything else you want to tell me that I haven’t asked you?

Explanation:

6 0

3 years ago

A volume of 100 mL of 1.00 M HCl solution is titrated with 1.00 M NaOH solution. You added the following quantities of 1.00 M Na

s344n2d4d5 [400]

Answer:

a: before equivalence point

b: equivalence point

c: before equivalence point

d: after the eqivalence point

e: before equivalence point

f: after the eqivalence point

Explanation:

Balanced equation of reaction:

NaOH +HCl =NaCl +H2O;

Volume of HCl is fixed and it 100ml and concentration is 1.0M

N1 and N2 normality of HCl and NaOH respectively;

V1 and V2 volume of HCl and NaOH respectively;

we have given molarity but we need normality;

$Normality=molarity \times n-factor$

<em>but in case of NaOH and HCl n-factor is 1 for each.</em>

hence

normality=molarity;

At equivalence point: $N_1V_1=N_2V_2$

Before equivalence point : $N_1V_1>N_2V_2$

After the equivalence point: $N_1V_1$

$N_1V_1=100\times1=100$

case a: 5.00 mL of 1.00 M NaOH

$N_2V_2=5\times1=5$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case b: 100mL of 1.00 M NaOH

$N_2V_2=100\times1=100$

$N_1V_1=N_2V_2$ hence it is equivalence point

case c: 10.0 mL of 1.00 M NaOH

$N_2V_2=10\times1=10$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case d: 150 mL of 1.00 M NaOH

$N_2V_2=150\times1=150$

$N_1V_1$ hence it is after the eqivalence point

case e: 50.0 mL of 1.00 M NaOH

$N_2V_2=50\times1=50$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case f: 200 mL of 1.00 M NaOH

$N_2V_2=200\times1=200$

$N_1V_1$ hence it is after the eqivalence point

7 0

3 years ago

What will happen to the temperature<br> when KCI is added to water?

Anna35 [415]

Answer:

As potassium chloride (KCl) dissolves in water, the ions are hydrated. ... Ion-dipole forces attract the positive (hydrogen) end of the polar water molecules to the negative chloride ions at the surface of the solid, and they attract the negative (oxygen) ends to the positive potassium ions.

7 0

2 years ago