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lys-0071 [83]
1 year ago
7

Name the following alkane:

Chemistry
1 answer:
vladimir1956 [14]1 year ago
4 0

The names of the alkanes are 2,2- dimethylbutane, 2,4- dimethylhexane, 2,2,3,3- tetramethylbutane and 4- ethyl, 3,6- dimethyl heptane.

Alkanes are saturated hydrocarbon in the organic chemistry. These are organic compounds that consists of single bonded carbon and hydrogen atoms. The common formula for writing an alkane is given by CₙH₂ₙ₊₂.

Alkanes are further divided into three more types which are:

1. Chain alkanes

2. Cycloalkanes

3. Branched alkanes

Hydrogenation method is used for preparation of alkanes from alkene and alkyne.

The names of the given compounds are:

Part A:

2,2- dimethyl butane

Part B:

2,4- dimethyl hexane

Part C:

2,2,3,3- tetramethyl butane

Part D:

4- ethyl, 3,6- dimethyl heptane

Learn more about alkanes from the link given below.

brainly.com/question/16837399

#SPJ1

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Refrigerators are usually kept at about 5°C, while room temperature is about 20°C. if you were to take an empty sealed 2 liter s
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c) No, because Celsius is not an absolute temperature scale

Explanation:

converting  5 oC to kelvin which is the absolute temperature scale gives = 273 + 5 = 278 K

and converting 20 oC to kelvin = 20 + 273 = 293 K

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The air pressure inside a submarine is 0.832atm. What would the pressure be in mnhg
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632.32 mmHg

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It is the monometric unit of pressure. It is define as "The pressure exerted by the column pf mercury at the height of 1 millimetre.

It is represented as mmHg.

It can also be written as mm Hg.

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It is barometric pressure, define as "The force exerted by atmospheric column on per unit area".

It is written as "atm".

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3 years ago
An engine operates on a Carnot cycle that uses 1mole of an ideal gas as the
sattari [20]

Answer:

Step 1;

q = w = -0.52571 kJ, ΔS = 0.876 J/K

Step 2

q = 0, w = ΔU = -7.5 kJ, ΔH = -5.00574 kJ

Explanation:

The given parameters are;

P_i = 100 N·m

T_i = 327 K

P_f = 90 N·m

Step 1

For isothermal expansion, we have;

ΔU = ΔH = 0

w = n·R·T·ln(P_f/P_i) = 1 × 8.314 × 600.15 × ln(90/100) = -525.71

w ≈<em> -0.52571</em> kJ

At state 1, q = w = -0.52571 kJ

ΔS = -n·R·ln(P_f/P_i) = -1 × 8.314 × ln(90/100) ≈ 0.876

ΔS ≈ 0.876 J/K

Step 2

q = 0 for adiabatic process

ΔU = 25×(27 - 327) = -7,500

w = ΔU = <em>-7.5 kJ</em>

ΔH = ΔU + n·R·ΔT

ΔH = -7,500 + 8.3142 × 300 = -5,005.74

ΔH = ΔU = <em>-5.00574 kJ</em>

6 0
2 years ago
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