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Vesnalui [34]
3 years ago
10

Simplify and Show your work

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
6 0

1.\frac{ 5( {4x}^{3}  {y}^{2} ) ^{3}}{( {4x}^{5} {y}^{3}) ^{4}   } \\  =  \frac{5 \times  {4}^{3}  \times {x}^{3 \times 3}  \times  {y}^{2 \times 3}  }{ {4}^{4}  \times  {x}^{5 \times 4} \times  {y}^{3 \times 4}   }  \\  =  \frac{5 \times 64 \times  {x}^{9} \times  {y}^{6}  }{256 \times  {x}^{20} \times  {y}^{12}  }  \\  =  \frac{320 {x}^{9} {y}^{6}  }{256 {x}^{20}  {y}^{12} }  \\  =  \frac{5 {x}^{9 - 20}  {y}^{6 - 12} }{4}  \\  =  \frac{5}{4 {x}^{11}  {y}^{6} }

2. {3}^{5x - 4}  =  {9}^{2x + 12}  \\  =  > {3}^{5x - 4}  =  {3}^{2(2x + 12)}  \\ =  >  {3}^{5x - 4}  =  {3}^{4x + 24}  \\ =  > 5x - 4 = 4x + 24 \\  =  > 5x - 4x = 24  + 4 \\  =  > x = 28

Hope you could understand.

If you have any query, feel free to ask.

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Answer:

Total no of ways can a combo containing 2 burgers, 3 different sides, 2 different flavor drinks, and 3 ice cream flavors be made = 529,200

Step-by-step explanation:

Given -

A fast-food restaurant offers 6 different burgers, 6 different side orders, 7 different flavor drinks, and 9 different flavors of ice cream .

choose 2 burgers from 6 different burger = \binom{6}{2}

choose 3 different sides from  6 different side orders = \binom{6}{3}

choose 2 flavor drinks from 7 different flavor drinks = \binom{7}{2}

choose 3 ice cream from   9 different flavors of ice cream = \binom{9}{3}

Total no of ways can a combo containing 2 burgers, 3 different sides, 2 different flavor drinks, and 3 ice cream flavors be made=

= \binom{6}{2}\times\binom{6}{3}\times\binom{7}{2}\times\binom{9}{3}          ( Using combination )

= \frac{6!}{(2!)(4!)}\times\frac{6!}{(3!)(3!)}\times\frac{7!}{(2!)(5!)}\times\frac{9!}{(3!)(6!)}

= 15\times20\times21\times84

= 529,200

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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