Answer:
x^0 y^-3 / x^2 y^-1
= 1 / x^2 y^-1 (y^3) ...because x^0 = 1 and [(y^-1) (y^3)] = y^2
= 1/(x^2 y^2)
Answer:
y=-3x+7
Step-by-step explanation:
y=mx+b is the formula you are going to end up once completed.
This, by given two points:
(4,-5) (3,-2)
= Point-Slope Intercept Form
= After subtracting both from above
-3 = is your slope, decreasing.
Substitute -3 for y=mx+b
y=-3x+b
Use one of the given points (any) to find what b equals.
(4,-5)
x y
-5=-3(4)+b
-5= -12+b
7=b
Final Equation:
y=-3x+7
The sum of two numbers is 13 more than twice the first number:
x + y = 2x +13
x - y = y - 14
solve the system of equations:
x - (x + 13) = (x +13) - 14
x = -12
y = 1
Answer:
the correct answer is A
Step-by-step explanation: