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Oksi-84 [34.3K]
2 years ago
8

1. A 250g chunk of metal is heated with 400 joules of energy and the temperature goes from 20 °C to 25°C. What is its specific h

eat ?
pls help me
Chemistry
1 answer:
Paha777 [63]2 years ago
5 0

The specific heat capacity of this chunk of metal is equal to 0.32 J/g°C.

<u>Given the following data:</u>

  • Mass of metal = 250g
  • Quantity of energy = 400 Joules
  • Initial temperature = 20°C
  • Final temperature = 20°C

To determine the specific heat capacity of this chunk of metal:

<h3>The formula for quantity of heat.</h3>

Mathematically, quantity of heat is given by the formula;

Q = mc\theta

<u>Where:</u>

  • Q represents the quantity of heat.
  • m represents the mass of an object.
  • c represents the specific heat capacity.
  • ∅ represents the change in temperature.

Making c the subject of formula, we have:

c = \frac{Q}{m\theta}

Substituting the given parameters into the formula, we have;

c = \frac{400}{250 \times (25-20)}\\\\c = \frac{400}{250 \times 5}\\\\c = \frac{400}{1250 }

Specific heat, c = 0.32 J/g°C.

Read more on specific heat here: brainly.com/question/2834175

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Explanation:

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Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})+(\frac {\%\ of\ the\ third\ isotope}{100}\times {Mass\ of\ the\ third\ isotope})+(\frac {\%\ of\ the\ fourth\ isotope}{100}\times {Mass\ of\ the\ fourth\ isotope})+(\frac {\%\ of\ the\ fifth\ isotope}{100}\times {Mass\ of\ the\ fifth\ isotope})

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For second isotope:

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For third isotope:

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For fourth isotope:

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For fifth isotope:

% = 0.904 %

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Thus,  

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Average atomic mass = 58.51047 amu

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