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Oksi-84 [34.3K]
2 years ago
8

1. A 250g chunk of metal is heated with 400 joules of energy and the temperature goes from 20 °C to 25°C. What is its specific h

eat ?
pls help me
Chemistry
1 answer:
Paha777 [63]2 years ago
5 0

The specific heat capacity of this chunk of metal is equal to 0.32 J/g°C.

<u>Given the following data:</u>

  • Mass of metal = 250g
  • Quantity of energy = 400 Joules
  • Initial temperature = 20°C
  • Final temperature = 20°C

To determine the specific heat capacity of this chunk of metal:

<h3>The formula for quantity of heat.</h3>

Mathematically, quantity of heat is given by the formula;

Q = mc\theta

<u>Where:</u>

  • Q represents the quantity of heat.
  • m represents the mass of an object.
  • c represents the specific heat capacity.
  • ∅ represents the change in temperature.

Making c the subject of formula, we have:

c = \frac{Q}{m\theta}

Substituting the given parameters into the formula, we have;

c = \frac{400}{250 \times (25-20)}\\\\c = \frac{400}{250 \times 5}\\\\c = \frac{400}{1250 }

Specific heat, c = 0.32 J/g°C.

Read more on specific heat here: brainly.com/question/2834175

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Answer:

The mass, CO2 and CO3 from the limestone sample is discussed below in details.

Explanation:

(A) mass loss of sample of limestone after 20 min

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From the given reaction of limestone, 2 mol of the sample gives 2 moles of CO 2.

Therefore  

184.4 g ( molar mass of limestone) gives2× 44 g of carbon dioxide.

1 g of sample gives 88/184.4 g of carbon dioxide

Hence 0.2458 g sample gives

= 88/184.4 × 0.2458 g = 0.117 g carbon dioxide

(B) mole of CO 2 lost = weight/ molar mass

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(C). 1 mol of limestone contain 2 mol of carbonate ion

From the reaction we know that carbonate ion of limestone is converted into carbondioxide

Hence lost carbonate ion = 0.2458 g

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1 mol limestone contain 1mol CaCO​​​ 3

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8 0
3 years ago
If 125g of KClO3 is heated, what is the total mass of the products?​
Andrej [43]

Given parameters:

Mass of KClO₃  = 125g

Unknown:

Total mass of the products = ?

When  KClO₃ is heated, it thermally decomposes to KCl and O₂ according to the chemical equation below;

               2KClO₃  →  2KCl + 3O₂

All chemical equations obeys the law of conservation of matter and with this regard, we know that the amount of reactants used is the same as that of the product.

The total mass of the products must give us 125g according to this law of conservation of matter.

Now to find the masses of each product,

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     Number of moles  = \frac{mass}{molar mass}

  molar mass of  KClO₃  = 39 + 35.5 + 3(16)  = 122.5g/mol

    So number of moles of KClO₃ = \frac{125}{122.5}  = 1.02moles

    2. Now, using this number of moles, find the number of moles of the products using this value;

   2 moles of KClO₃ produced 2 moles of KCl

  1.02 moles of KClO₃ will also produce 1.02moles of KCl

   2 moles of KClO₃ produced 3 moles of O₂

   1.02 moles of KClO₃ will produce   \frac{1.02 x 3} {2} mole = 1.53 moles of O₂

   3. Now find the masses of each product;

Mass  = number of moles x molar mass

  molar mass of KCl  = 39 + 35.5 = 74.5g/mol

  molar mass of O₂  = 16 x 2  = 32g/mol

  Mass of KCl  = 74.5 x 1.02  = 75.99g

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Total mass of products = mass of KCl + Mass of O₂ = 75.99g + 48.96g

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Saturated solutions are defined as the solutions where no more solute particles can be dissolved in the solvent.  The concentration of the solute particles that can be dissolved in a solution is maximum.

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