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coldgirl [10]
4 years ago
6

Any info on Neptunes spot? I need it for a project.

Chemistry
1 answer:
LUCKY_DIMON [66]4 years ago
3 0

Here's one! those spots are actually storms:)


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What else is produced during the combustion of butane, C4H10?
denpristay [2]

Another product: CO₂

<h3>Further explanation</h3>

Given

Reaction

2C₄H₁₀ + 13O₂⇒ 8__+ 10H₂O

Required

product compound

Solution

In the combustion of hydrocarbons there can be 2 kinds of products

If there is excess Oxygen, you will get Carbon dioxide(CO₂) and water in the product

If Oxygen is low, you'll get Carbon monoxide(CO) and water

Or in other ways, we can use the principle of the law of conservation of mass which is also related to the number of atoms in the reactants and in the products

if we look at the reaction above, there are C atoms on the left (reactants), so that in the product there will also be C atoms with the same number of C atoms on the left

2C₄H₁₀ + 13O₂⇒ 8CO₂+ 10H₂O

5 0
3 years ago
Read 2 more answers
Which bond will each pair of elements form?
jok3333 [9.3K]

Explanation: Sodium is a metal with a low electronegativity it will form an ionic bond with a non metal with a high electronegativity.

Both Florine and Sulfur are non metals with high electronegativity.

Neon is a noble gas family VIII A and normally doesn't form any bonds at all.

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7 0
3 years ago
A piece of an unknown substance weighing 124.0 grams is heated in boiling water to 100.0oc. when the substance is placed in a ca
MakcuM [25]

The heat cause 300g water temperature increase from 20 to 26 celcius. The heat transferred would be: 300g * (26 °C -20 °C) *4.2 joule/gram °C= 7560J

The unknown substance is added to the water, so its final temperature should be the same as the water. The calculation would be:

7560J= 124g * (100-26)* specific heat

specific heat= 7560J / 124g / 74 °C= 0.8238 J/gram °C

3 0
4 years ago
Why is blue so rare in nature?​
vladimir1956 [14]

Answer:

Explanation:

For a flower to appear blue, "it needs to be able to produce a molecule that can absorb very small amounts of energy," in order to absorb the red part of the spectrum, Kupferschmidt said.

7 0
2 years ago
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3-ethyl-2-methyl-2-pentene
gayaneshka [121]
See photo for drawing :)

3 0
4 years ago
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