Answer:
1019.27 g.
Explanation:
- For the balanced reaction:
<em>2Na + Cl₂ → 2NaCl,</em>
It is clear 2 moles of Na with 1 mole of Cl₂ to produce 2 moles NaCl.
- Firstly, we need to calculate the no. of moles of Cl₂ is needed to react with 57.5 mol Na:
2 moles of Na need → 1 mol of Cl₂, from the stichiometry.
57.5 moles of Na need → ??? mol of Cl₂.
<em>∴ The no. of moles of Cl₂ is needed to react with 57.5 mol Na =</em> (1 mol)(57.5 mol)/((2 mol) <em>= 28.75 mol.</em>
<em>∴ the mass of Cl₂ is needed to react with 57.5 mol Na = (no. of moles of Cl₂)(molar mass of Cl₂) =</em> (28.75 mol)(35.453 g/mol) <em>= 1019.27 g.</em>
True
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Answer:
pH = 4.45
Explanation:
We need to find the pH of
solution of HCl. We know that, pH of a solution is given by :
![pH=-log[H]^+](https://tex.z-dn.net/?f=pH%3D-log%5BH%5D%5E%2B)
Put all the values,
![pH=-log[3.5\times 10^{-5}]\\\\pH=4.45](https://tex.z-dn.net/?f=pH%3D-log%5B3.5%5Ctimes%2010%5E%7B-5%7D%5D%5C%5C%5C%5CpH%3D4.45)
So, the pH of the solution of HCl is 4.45.
the algal population will decrease.