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erica [24]
2 years ago
15

How many atoms of Bi are there in a 41.8 g sample?

Chemistry
1 answer:
Alekssandra [29.7K]2 years ago
3 0

Answer:

The number of particles in the 41.8g sample of Bismuth is 12.044 × 10²³

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igomit [66]

Hello,

In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “sea” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions.

Hope this helps!!!! Happy Holidays!!!! (:

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3 years ago
Please help!!! (im really bad at chemistry)
Lubov Fominskaja [6]

Answer:

1000ml/1L

Explanation:

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What is the process called when a solid turns to a gas
maxonik [38]
When a solid turns to gas it is called sublimation, and when a gas turns into a liquid it is called deposition 
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3 years ago
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Determine the standard enthalpy of formation in kJ/mol for NO given the following information about the formation of NO2 under s
Zarrin [17]

Answer:

90.3 kJ/mol

Explanation:

Let's consider the following thermochemical equation.

2 NO(g) + O₂(g) → 2 NO₂(g)  ∆H°rxn = –114.2 kJ

We can find the standard enthalpy of formation for NO using the following expression.

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × ΔH°f(O₂(g))

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g)) - 1 mol × 0 kJ/mol

∆H°rxn = 2 mol × ΔH°f(NO₂(g)) - 2 mol × ΔH°f(NO(g))

ΔH°f(NO(g)) = (2 mol × ΔH°f(NO₂(g)) - ∆H°rxn) / 2 mol

ΔH°f(NO(g)) = (2 mol × 33.2 kJ/mol + 114.2 kJ) / 2 mol

ΔH°f(NO(g)) = 90.3 kJ/mol

8 0
3 years ago
Caleb has a 860-kilogram car sitting in his back yard, gathering rust.
emmasim [6.3K]
<h3>Answer:</h3>

A. 860 kg

<h3>Explanation:</h3>

To answer the question we need to understand that;

  • Mass refers to the amount of matter in an object.
  • Weight, on the other hand, refers to the gravitational pull of an object to a given surface.
  • Mass is measured using a spring balance.

We also need to know that;

  • The mass of an object remains constant every where irrespective of the gravitational acceleration.
  • Therefore, an object on the surface of the earth would have the same mass as on the surface of the moon.
  • In this case; the mass of the car remains the same on the outer space as on the back yard.
3 0
3 years ago
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